Answer:
The boiling point of a 8.5 m solution of Mg3(PO4)2 in water is<u> 394.91 K.</u>
Explanation:
The formula for molal boiling Point elevation is :
= elevation in boiling Point
= Boiling point constant( ebullioscopic constant)
m = molality of the solution
<em>i =</em> Van't Hoff Factor
Van't Hoff Factor = It takes into accounts,The abnormal values of Temperature change due to association and dissociation .
In solution Mg3(PO4)2 dissociates as follow :
Total ions after dissociation in solution :
= 3 ions of Mg + 2 ions of phosphate
Total ions = 5
<em>i =</em> Van't Hoff Factor = 5
m = 8.5 m
= 0.512 °C/m
Insert the values and calculate temperature change:
Boiling point of pure water = 100°C = 273.15 +100 = 373.15 K
= 373.15 K[/tex]
21.76 = T - 373.15
T = 373.15 + 21.76
T =394.91 K
Answer:
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Explanation:
<u>1. Balanced molecular equation</u>
<u>2. Mole ratio</u>
<u>3. Moles of HNO₃</u>
- Number of moles = Molarity × Volume in liters
- n = 0.600M × 0.0100 liter = 0.00600 mol HNO₃
<u>4. Moles Ba(OH)₂</u>
- n = 0.700M × 0.0310 liter = 0.0217 mol
<u>5. Limiting reactant</u>
Actual ratio:
Since the ratio of the moles of HNO₃ available to the moles of Ba(OH)₂ available is less than the theoretical mole ratio, HNO₃ is the limiting reactant.
Thus, 0.006 moles of HNO₃ will react completely with 0.003 moles of Ba(OH)₂ and 0.0217 - 0.003 = 0.0187 moles will be left over.
<u>6. Final molarity of Ba(OH)₂</u>
- Molarity = number of moles / volume in liters
- Molarity = 0.0187 mol / (0.0100 + 0.0031) liter = 0.456M
Answer: 1. Is2 2s2 2p3
2. Nitrogen
Explanation: The number of electron present In C = 6
But an extra electron is added since the charge on C is -1, this therefore makes the total electron 7.
1. By arrangement, the Electronic configuration is therefore;
Ans: 1s2 2s2 2p3
2. It is explained how C has 7 electrons, we can proceed then.
Neutral atom have atomic number of 7.
The element with atomic number of 7 is;
Ans: NITROGEN
Kepler’s third law exhibits the relationships between the distance of a planet from the sun and the period of its revolution. Kepler’s third law is also sometimes referred to as the law of harmonies.
Kepler’s third law compares the orbital period and the radius of an orbit of a planet to the distance of the planet to the sun. It states mathematically that the more distant a planet is from the sun the greater its orbital period will be. The period of revolution of a planet is measured in days, weeks, months or years. For example, Earth’s period of revolution is 365 days.
