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astra-53 [7]
3 years ago
15

Assume that a raindrop has a volume of 3.48 cm3. If you had an Avogadro’s number of raindrops that just filled a cubic box. What

would be the edge of the length of the box measured in kilometers?
Chemistry
1 answer:
N76 [4]3 years ago
6 0
Answer is: <span>edge of the length of the box measured is 1280,57 kilometers.
</span>V(raindrop) = 3,48 cm³.
V(cubic box) = 3,48 cm³ · 6,023·10²³.
V(cubic box) = 2,1·10²⁴ cm³.
V(cubic box) = 2,1·10²⁴ cm³ ÷ 10¹⁵.
V(cubic box) = 2,1·10⁹ km³.
r(cubic box) = ∛2,1·10⁹ km³.
r(cubic box) = 1280,57 km.
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Answer:

\boxed {\boxed {\sf 1.5935 \ mol \ FeCl_}}

Explanation:

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Multiply by the given number of grams.

258.45 \ g \ FeCl_3 *\frac {162.19 \ g\ FeCl_3}{1 \ mol \ FeCl_3}

Flip the ratio so the grams of iron (III) chloride cancel.

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\frac {258.45  \ mol \ FeCl_3}{162.19}

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The original measurement of grams has 5 significant figures, so our answer must have the same. For the number we calculated, that is the ten thousandth place.

1.5935 \ mol \ FeCl_3

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