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spayn [35]
3 years ago
12

What was the key characteristic by which Dmitri Mendeleev arranged his periodic table? A. increasing atomic number B. electron c

onfiguration C. decreasing atomic number D. increasing atomic mass
Chemistry
2 answers:
valentina_108 [34]3 years ago
4 0
I think the correct answer from the choices listed above is option A. The key characteristic by which Dmitri Mendeleev arranged his periodic table was that the elements are arranged in increasing atomic number. Hope this answers the question.
Anastasy [175]3 years ago
4 0

Answer:  D. increasing atomic mass

Explanation:  Dmitri Mendeleev  arranged the periodic table on the basis of the increasing atomic mass.

He observed the physical and chemical properties of the elements and he found that these properties are related to their atomic masses. Thus he arranged these elements on the basis of the physical and chemical properties into different kinds of groups.

Thus elements with similar property was arranged in the same group.

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What are the very reactive gasses of the periodic table called
kipiarov [429]

the very reactive gasses of the periodic table are called halogens.

4 0
4 years ago
Read 2 more answers
Where do you find elements grouped that have the most similar physical and chemical properties?
Svetach [21]

Answer:

Each element within a group has similar physical or chemical properties because of its atom's outermost electron shell (most chemical properties are dominated by the orbital location of the outermost electron).

Explanation:

6 0
3 years ago
What is the formula for measuring volume in Chemistry?
fredd [130]
For the volume of a solid or liquid
Density = mass/ volume so
volume = mass / density

For the volume of a liquid
Moles = volume x concentration
Volume = moles / concentration

For the volume of a gas
Volume = moles x 24

There are many other formulas as well :)
3 0
4 years ago
What volume of water must be added
stellarik [79]

Answer:

litre.50000665432158900643212lo

3 0
3 years ago
Assuming dopant atoms are uniformly distributed in a silicon crystal, how far apart are these atoms when the doping concentratio
enyata [817]

Answer:

d =~ 5.8μm

d =~ 0.13 μm

Explanation:

when the doping concentrations are 5 × 10^15 cm^-3

d = v^-1/3  ; where d represent the distance between the atoms , and v  represent the volume

d =1/ ∛v

d = 1/ ∛5 × 10^15

d = 1/ 170997.5

d = 5.85 × 10 ^ -6

d =~ 5.8μm

when the doping concentrations are 5 × 10^20 cm^-3

d = v^-1/3  ; where d represent the distance between the atoms , and v  represent the volume

d =1/ ∛v

d = 1/ ∛5 × 10^20

using the principle of surds and standard forms, we have

d = 1/ ∛0.5 × 10^21  

d = 1/7937005.26

d = 1.26 × 10 ^ -7

d = 0.126 × 10 ^ -6

d =~ 0.13 μm

8 0
3 years ago
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