Question

A balloon is filled with 30.0 L of helium in the morning when the temperature is 25.00 ℃. By noon the temperature has risen to 55.00 ℃. Determine the new volume of the balloon. *

Answer 1

Answer:

33.0 L

Explanation:

Step 1: Given data

• Initial volume of the balloon (V₁): 30.0 L

• Initial temperature (T₁): 25.00 °C

• Final volume of the balloon (V₂): ?

• Final temperature (T₂): 55.00 °C

Step 2: Convert the temperatures to the Kelvin scale

We will use the following expression.

K = °C + 273.15

T₁: K = 25.00°C + 273.15 = 298.15 K

T₂: K = 55.00°C + 273.15 = 328.15 K

Step 3: Calculate the final volume of the balloon

If we assume ideal behavior, we can calculate the final volume of the balloon using Charles' law.

V₁/T₁ = V₂/T₂

V₂ = V₁ × T₂/T₁

V₂ = 30.0 L × 328.15 K/298.15 K = 33.0 L