Answer:
The rapid movement of excess charge from one place to another is an <em>electric discharge.</em>
Explanation:
A material in which electrons <em>CANNOT</em> move easily from place to place is an insulator. A material in which electrons <em>CAN </em>move easily from place to place is a conductor.
Answer:
0.50 M is the molar concentration of
.
Explanation:
The equilibrium constant of the reaction = 

Equilibrium concentration of
= 0.050 M
![[NO_2]=0.050 M](https://tex.z-dn.net/?f=%5BNO_2%5D%3D0.050%20M)
Equilibrium concentration of
= ?
![[N_2O_4]= x](https://tex.z-dn.net/?f=%5BN_2O_4%5D%3D%20x)
The equilibrium constant of the reaction is given aSL:
![K_c=\frac{[NO_2]^2}{[N_2O_4]}](https://tex.z-dn.net/?f=K_c%3D%5Cfrac%7B%5BNO_2%5D%5E2%7D%7B%5BN_2O_4%5D%7D)


0.50 M is the molar concentration of
.
Try sugar. I hope this helps!!!!!
Answer:
ΔG° is for ideal (fixed) or standard conditions which cannot be found at the cellular level while ΔG is dependent on the quantities of reactants and products present at a specific time
Explanation:
ΔG° is fixed value for a given reaction that indicates the direction in which the reaction will proceed in a chemical equation under ideal conditions and because conditions within a cell varies and are unlike standard conditions, ΔG° cannot predict the direction of a cellular reaction at any given time. To predict the direction of progression of a reaction within the cell, ΔG is used, which depends on the amounts of the reactants and products present at a particular time
Answer:
Isopropyl propionate
Explanation:
1. Information from formula
The formula is C₆H₁₂O₂. A six-carbon alkane would have the formula C₆H₁₄. The deficiency of two H atoms indicates the presence of either a ring or a double bond.
2. Information from the spectrum
(a) Triplet-quartet
A 3H triplet and a 2H quartet is the classic pattern for a CH₃CH₂- (ethyl) group
(b) Septet-doublet
A 1H septet and a 6H doublet is the classic pattern for a -CH(CH₃)₂ (isopropyl) group
(c) The rest of the molecule
The ethyl and isopropyl groups together add up to C₇H₁₂.
The rest of the molecule must have the formula CO₂ and one unit of unsaturation. That must be a C=O group.
The compound is either
CH₃CH₂-COO-CH(CH₃)₂ or (CH₃)₂CH-COO-CH₂CH₃.
(d) Well, which is it?
The O atom of the ester function should have the greatest effect on the H atom on the adjacent carbon atom.
The CH of an isopropyl is normally at 1.7. The adjacent O atom should pull it down perhaps 3.2 units to 4.9.
The CH₂ of an ethyl group is normally at 1.2. The adjacent O atom should pull it down to about 4.4.
We see a signal at 5.0 but none near 4.4. The compound is isopropyl propionate.
3. Summary
My peak assignments are shown in the diagram below.