Answer:
548s = t
Explanation:
A first-order reaction has as general equation:
![ln \frac{[A]_t}{[A]_0} = -kt](https://tex.z-dn.net/?f=ln%20%5Cfrac%7B%5BA%5D_t%7D%7B%5BA%5D_0%7D%20%3D%20-kt)
Where ![[A]_t](https://tex.z-dn.net/?f=%5BA%5D_t)
is the concentration of the reactant in the time t, ![[A]_0](https://tex.z-dn.net/?f=%5BA%5D_0)
is the initial concentration of the reactant, k is rate constant and t is time. Replacing with values of the problem:
-1.65 = -3.00x10⁻³s⁻¹×t
<em>548s = t</em>
<em></em>
I hope it helps!
The first step of the oxidation of a primary alcohol involves conversion to an aldehyde via the elimiination of a hydrogen molecule. Thus, ClCH2CH2CH2OH becomes ClCH2CH2COH, which is 3-chloropropanal.
A white insoluble solid would appeaer
PH=-log[H⁺]
That means that the pH=-log(3.3×10)=-1.52
I hope this helps. Let me know if anything is unclear.
Answer:-
5
Explanation:-
Chemical formula for calcium oxide = CaO
Chemical formula of water = H2O
Chemical Formula of Calcium Hydroxide = Ca(OH)2
Mass of Ca(OH)2 = 370g
Molar mass of Ca(OH)2 = 40 x 1 + ( 16 x 1 + 1 x 1 ) x 2
= 74 g mol-1
Number of moles of Ca(OH)2 = 370 g / 74 g mol-1
= 5 moles
The balanced chemical equation for this process is
CaO + H2O --> Ca(OH)2
From the equation we see
For 1 mol of Ca(OH)2 to form, 1 mol of CaO is needed to react.
For 5 mol of Ca(OH)2 to form, 5 x 1 / 1 = 5 mol of CaO is needed to react.
