Step-by-step explanation:
A ball is launched straight up in the air from a height of 6 feet. The velocity as a function of time t is given by :
f(t) = -32 t+285
Height of the ball is :
C is constant. Here the ball is launched from a height of 6 feet. So,
At t = 2 s, 
At t = 9 s, 
Between 2 s and 9 s, the ball's height changed is : 1275 - 512 = 763 m.
Answer:
x = 20 but see below.
Step-by-step explanation:
Remark.
This is not well enough marked to know whether D = A or whether you have to do some algebra to find the relationship between A and D. So I will assume A = D and then I'll solve it so you have to manipulate A and D.
A = D
3x - 10 = 2x + 10 Add 10 to both sides
3x - 10 + 10 = 2x + 10 + 10 Cancel
3x = 2x + 20 Subtract 2x from both sides
3x-2x=2x-2x + 20
x = 20
A = E
If A = E then to find x you have to add 3 angles together.
E + D + 45 = 180 Add the three angles of the triangle
E + D = 180 - 45 Subtract 45 from both sides
E + D = 135 Substitute for D and E
3x - 10 + 2x + 10 = 135 Combine like terms
5x = 135 Divide by 5
x = 135 / 5
x = 27
Answer
I'd go with the first one.
The mean is the average of a set of numbers. So to do that:
add all the numbers 120+235+98+142=$595
Then divide that by the total number in the set, in this case it is 4.
$595/4= $148.75 assuming that the prices given are the final price of the job.
He will need 12 sq. inches of Paper for each rhombus.
Given: 6 inches tall and 4 inches wide.
so, Length of the diagonals are 6 and 4 inches respectively.
Refer to figure.
The two diagonals cuts the rhombus into four equal parts, so
Area of one rhombus = 4 x (area of 1 part of the rhombus)
Now,
Area of 1 part of the rhombus = 
x 3 x 2
= 3 sq. inches
Area of one rhombus = 4 x 3 = 12 sq. inches
Hence, 12 sq. inches of Paper is needed for each rhombus.
Learn more about the "Finding the area of the rhombus" Here : brainly.com/question/10684261
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Hello,
any point equidistant from the ends of a segment belongs to the perpendicular bisector of the segment.
|AD|=|BD| and |AC|=|BC|
