The volume of the car is 1800cm^3 which is equivalent to 0.0018m^3
<h3>Scale modelling</h3>
Given the scale factor that model of a car is amde to a scale of 1:40, Giving that the model as 45cm^3, this means that;
1 = 45cm^2
Determine the volume of the car
40 = x
Find the ratio
1/40 = 45/x
x = 40*45
x = 1800cm^3
x = 0.0018m^3
Hence the volume of the car is 1800cm^3 which is equivalent to 0.0018m^3
Learn more on scale factor here; brainly.com/question/25722260
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Answer:


Step-by-step explanation:
Given


Solving (a); Point estimate of mean
To do this, we simply calculate the sample mean




Solving (b); Point estimate of standard deviation
To do this, we simply calculate the sample standard deviation





<em>Note that: The sample mean and the sample standard deviation are the best point estimators for the mean and the standard deviation, respectively.</em>
<em>Hence, the need to solve for sample mean and sample standard deviation</em>
Answer:
John answered 50 questions.
Step-by-step explanation:
Although five of John's answers were incorrect, 90% of his answers were correct.
This means that 5 is 100 - 90% = 10% of the total number of questions, n. So



John answered 50 questions.
Answer:
1. 
2. ![x=\pm7i[tex]3.[tex]\pm 12x =a](https://tex.z-dn.net/?f=x%3D%5Cpm7i%5Btex%5D%3C%2Fp%3E%3Cp%3E3.%5Btex%5D%5Cpm%2012x%20%3Da)
4. 22
Step-by-step explanation:
1. 



2. 


![x=\pm7i[tex]3. Area of square = [tex]a^{2}](https://tex.z-dn.net/?f=x%3D%5Cpm7i%5Btex%5D%3C%2Fstrong%3E%3C%2Fp%3E%3Cp%3E%3Cstrong%3E3.%20Area%20of%20square%20%3D%20%5Btex%5Da%5E%7B2%7D)
Where a is the side
We are given an area o square = 
So, 


4. We are given that the solution of quadratic equation -9 and 9
So, equation becomes:


So, in the given equation 
z should be the number from which if we subtract 103 so we get 81
Substitute z = 22



Thus the value of z is 22