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____ [38]
3 years ago
10

After graphing What is the solution of y= -3x -1 and y= x + 3

Mathematics
1 answer:
Tresset [83]3 years ago
5 0

Answer: (3,4)

Step-by-step explanation:

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URGENT NEEDS TO ME SUBMITTED BY MIDNIGHT!! The ratio of girls to boys in Mr. Hansen’s class is 4:5. The ratio of girls to boys i
nadya68 [22]
If the ratio of girls to boys in Mr. Hansen's class is 4:5, and the ratio of girls to boys in Ms. Luna's class is 8:10, then the equation that correctly compares the ratio of both Mr. Hansen's class and Ms. Luna's class are 4/5 = 8/10.
3 0
3 years ago
Add 78, 139, and 14, and then divide by 44.
denpristay [2]

Answer:

5.24, 21/4, or 5 and 1/4

Step-by-step explanation:

78+139+14 = 231

231/44 = 5.25

Or 21/4 (improper fraction)

Or 5 and 1/4 (mixed number)

I'm not exactly sure what you were asking I hope that helps!

8 0
2 years ago
Find the surface area of a rectangular prism with base 4 m by 5 m and height 8 m.
Andre45 [30]

Answer:

Step-by-step explanation:

surface area=area of sides +area of top and bottom

=2(4+5)×8+2×(4×5)

=2[(9×8)+20]

=2[72+20]

=2×92

=184 m²

4 0
3 years ago
Read 2 more answers
The tennis team is having a fundraiser for uniforms for it’s nine players. the total cost for the uniforms is $759.84 and the te
Sonja [21]

Answer:

C. 9x + 224.36 ≥ 759.84

Step-by-step explanation:

If each team member raises x dollars, the 9 team members will have raised 9x dollars. That amount added to the amount they already have must equal or exceed the amount required:

9x + 224.36 ≥ 759.84 . . . . matches selection C

5 0
2 years ago
A The length of a rectangle is 4 m more
Lady bird [3.3K]

Given :

  • The length of a rectangle is 4m more than the width.
  • The area of the rectangle is 45m²

⠀

To Find :

  • The length and width of the rectangle.

⠀

Solution :

We know that,

\qquad { \pmb{ \bf{Length \times Width = Area_{(rectangle)}}}}\:

So,

Let's assume the length of the rectangle as x and the width will be (x – 4).

⠀

Now, Substituting the given values in the formula :

\qquad \sf \: { \dashrightarrow x  \times  (x - 4) = 45 }

\qquad \sf \: { \dashrightarrow {x}^{2}  - 4x = 45 }

\qquad \sf \: { \dashrightarrow {x}^{2}  - 4x - 45 = 0 }

\qquad \sf \: { \dashrightarrow {x}^{2}    - 9x+ 5 x - 45 = 0 }

\qquad \sf \: { \dashrightarrow x(x - 9) + 5(x - 9) = 0 }

\qquad \sf \: { \dashrightarrow (x  - 9) (x  + 5) = 0 }

\qquad \sf \: { \dashrightarrow x = 9, \: \: x =  - 5}

⠀

Since, The length can't be negative, so the length will be 9 which is positive.

⠀

\qquad { \pmb{ \bf{ Length _{(rectangle)} = 9\:m}}}\:

\qquad { \pmb{ \bf{ Width _{(rectangle)} = 9 - 4=5\: m}}}\:

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8 0
2 years ago
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