Ask question

Ask question

All categories

3 years ago

11

2) On Monday, the stock rose 6.25 points. Wednesday, the stock dropped 9 points. At the end of the week, the stock dropped anoth

er 3.5 points. What was the stock's value?

1 answer:

Darina [25.2K]3 years ago

5 0

Answer:

-6.25

Step-by-step explanation:

6.25 - 9= -2.75.

-2.75-3.5= -6.25

You might be interested in

Michael is using a drawing program to complete a construction. Which construction is he completing? A circle is drawn with two p

Cloud [144]

Answer: <span>A square inscribed in a circle.
</span>

Justification:

Note that by making two perpendicular lines that intersect each other in the center of the circle, he obtains 4 equidistant points on the circumference.

So, joining each pair of neighbouring points, the image will reveal 4 congruent sides joining at right angles (90°). This is the image of a square with the four vertices on the circumference.

5 0

3 years ago

The height h (in feet) of an object dropped from a ledge after x seconds can be modeled by h(x)=−16x2+36 . The object is dropped

kakasveta [241]

Check the picture below.

$\bf ~~~~~~\textit{initial velocity in feet} \\\\ h(t) = -16t^2+v_ot+h_o \quad \begin{cases} v_o=\textit{initial velocity}&\\ \qquad \textit{of the object}\\ h_o=\textit{initial height}&\\ \qquad \textit{of the object}\\ h=\textit{object's height}&\\ \qquad \textit{at "t" seconds} \end{cases}$

so the object hits the ground when h(x) = 0, hmmm how long did it take to hit the ground the first time anyway?

$\bf h(x)=-16x^2+36\implies \stackrel{h(x)}{0}=-16x^2+36\implies 16x^2=36 \\\\\\ x^2=\cfrac{36}{16}\implies x^2 = \cfrac{9}{4}\implies x=\sqrt{\cfrac{9}{4}}\implies x=\cfrac{\sqrt{9}}{\sqrt{4}}\implies x = \cfrac{3}{2}~~\textit{seconds}$

now, we know the 2nd time around it hit the ground, h(x) = 0, but it took less time, it took 0.5 or 1/2 second less, well, the first time it took 3/2, if we subtract 1/2 from it, we get 3/2 - 1/2 = 2/2 = 1, so it took only 1 second this time then, meaning x = 1.

$\bf ~~~~~~\textit{initial velocity in feet} \\\\ h(x) = -16x^2+v_ox+h_o \quad \begin{cases} v_o=\textit{initial velocity}&0\\ \qquad \textit{of the object}\\ h_o=\textit{initial height}&\\ \qquad \textit{of the object}\\ h=\textit{object's height}&0\\ \qquad \textit{at "t" seconds}\\ x=\textit{seconds}&1 \end{cases} \\\\\\ 0=-16(1)^2+0x+h_o\implies 0=-16+h_o\implies 16=h_o \\\\[-0.35em] ~\dotfill\\\\ ~\hfill h(x) = -16x^2+16~\hfill$

quick info:

in case you're wondering what's that pesky -16x² doing there, is gravity's pull in ft/s².

4 0

3 years ago

Marie is choosing a bag of apples to make into a pie. She thinks the pie will be tastier if it has more apples. The bag of green

Shalnov [3]

Answer:

I don't know what the question is but there will be 9.25 pounds of apples?

Step-by-step explanation:

3 0

2 years ago

Convert r=53sinθ−cosθ to rectangular form.

Helga [31]

Answer:

$y = \frac{1}{3} x + \frac{5}{3}$

Step-by-step explanation:

r = 5/(3sinθ-cosθ)

multiply both sides by (3sinθ-cosθ):

r(3sinθ-cosθ) = 5

expand:

3rsinθ-rcosθ = 5

replace rsinθ with y and rcosθ with x:

3y-x = 5

add x to both sides:

3y = x + 5

divide both sides by 3:

y = 1/3x + 5/3

: )

3 0

3 years ago

An expression is shown.

ahrayia [7]

Answer:

10x+2

Step-by-step explanation:

creo que es esa no se si esta bien

3 0

2 years ago