The satellite revolves around moon due to centripetal force which is provided by gravity in this context so we can equate gravity and centripetal force.

$mrw^{2} = \frac{GMm}{R^{2} }$

where, m is mass of satellite

M is mass of moon

ω is angular velocity

G is Universal gravitational constant

R is the radius of moon

from the above equation we get ω as,

$w=\sqrt{\frac{GM}{R^{3} } }$

$T = \frac{2\pi }{w}$

$T= 2\pi \sqrt{\frac{R^{3} }{GM} }$

here M = 7.36 X 10^22

R = 1.738 X 10^6

G =6.67 X 10^-11

$T= 2X3.14 \sqrt{\frac{(1.738 X 10^6)^{3} }{6.67 X 10^-11 X 7.36 X 10^22} }$

T= 6.50 X 10^3 seconds

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3 years ago

What factor most limits the energy available to producers in the tall grass prairie ecosystem? The amount of energy—

WITCHER [35]

Answer: D

Explanation:

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3 years ago

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