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gavmur [86]
3 years ago
8

How can you use the properties of multiplication to determine what the factors are

Mathematics
1 answer:
Mariulka [41]3 years ago
7 0
You cant if you are trying to figure out what the factors are
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Please help! i literally suck at geometry
sdas [7]
Don’t say like that!Think you can and you will achieve! :) :)
8 0
2 years ago
What is the value of x in the following equation.<br> -x ^3/2 = -27
Yuri [45]

Answer:

3^√54

Step-by-step explanation:

-x^3=-54

-x=3^√54

5 0
3 years ago
7p-(3p+4)= -2(2p-1) + 10<br> Solve each equation.
Aliun [14]
Perform the indicated multiplication:

<span>7p-(3p+4)= -2(2p-1) + 10

becomes 

7p - 3p - 4 = -4p + 2 + 10

Group like terms:

7p - 3p + 4p = 2 + 10 + 4

           8p      =   16 => p = 2 (answer)</span>
8 0
3 years ago
A study indicates that 37% of students have laptops. You randomly sample 30 students. Find the mean and the standard deviation o
Brilliant_brown [7]

Answer:

The mean and the standard deviation of the number of students with laptops are 1.11 and 0.836 respectively.

Step-by-step explanation:

Let <em>X</em> = number of students who have laptops.

The probability of a student having a laptop is, P (X) = <em>p</em> = 0.37.

A random sample of <em>n</em> = 30 students is selected.

The event of a student having a laptop is independent of the other students.

The random variable <em>X</em> follows a Binomial distribution with parameters <em>n</em> and <em>p</em>.

The mean and standard deviation of a binomial random variable <em>X</em> are:

\mu=np\\\sigma=\sqrt{np(1-p)}

Compute the mean of the random variable <em>X</em> as follows:

\mu=np=30\times0.37=1.11

The mean of the random variable <em>X</em> is 1.11.

Compute the standard deviation of the random variable <em>X</em> as follows:

\sigma=\sqrt{np(1-p)}=\sqrt{30\times0.37\times(1-0.37)}=\sqrt{0.6993}=0.836

The standard deviation of the random variable <em>X</em> is 0.836.

5 0
3 years ago
What is 158% of 200?
Amanda [17]
You would do 200 times 1.58 and that gets you 316 hope this helps :)
7 0
2 years ago
Read 2 more answers
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