Answer:
Hence by induction proved for all natural numbers n.
Step-by-step explanation:
we are to Prove with induction that all convex polygons with n≥3 sides have interior angles that add up to (n-2)·180 degrees.
Starting from triangle we can assume that angles of a triangle add up to 180
Imagine one side say AB. From A and B two lines are drawn to meet at D
Now BADC is a quadrilateral. The sum of angles of a quadrilateral would be sum of angles of two triangles namely ABC and BDC. hence these add up to 360.
Thus when we make n from 3 to 4 this is true.
Let us assume for n sides sum of angles is (n-2)180 degrees. Take one side vertices and draw two lines so that the polygon is n+1 sided. Now the total angles would be the sum of angles of original polygon+angles of new triangle = (n-2)180+1 = (n+1-2)180
Thus if true for n it is true for n+1. Already true for 3 and 4.
Hence by induction proved for all natural numbers n.
Answer:
-14x - 9y = 6
Step-by-step explanation:
subtract the similar terms from each other
-7x - 7x = -14x
-y - 8y = -9y
0 - - 6 = 0 + 6 = 6
put it together:
-14x - 9y = 6
hope this helps
Okay. To find this answer, all you have to do is the opposite of subtraction, which is addition. 24 + 12= 36. There. n = 36.
Q-2r=4, therefore: q=4+2r.
Plug the value of q into q+r=37, so you get:
4+2r+r=37
3r=37-4=33
3r=33
Therefore: r=11.
q-2r=4, but r=11, so:
q-2(11)=4
q-22=4
Therefore q=26.
Check if the answer is correct using second equation:
q=4+2r=4+2(11)=4+22=26.
So: q=26 and r=11.
Answer:
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