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Advocard [28]
3 years ago
3

Explain why sulfur aluminide is not a correct name for the ionic compound formed between sulfur and aluminum

Chemistry
2 answers:
Katena32 [7]3 years ago
6 0
Because the metal goes before the non metal. The correct way would be aluminum sulfide. This is an ionic compound.
Georgia [21]3 years ago
3 0

Answer:

Sulfur aluminide is not a correct name because an aluminide is a compound that has aluminium with more electropositive elements, and sulfur is less electropositive (or more electronegative) than aluminium.

The correct name for this compound is Aluminum sulfide with the formula Al2S3.

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10. 17.5 g of NaOH were dissolved in 350 mL of water. The solution was titrated with HNO3 to a methyl orange endpoint (methyl or
Tomtit [17]

1747.2 ml of HNO3 is required to reach methyl orange endpoint.

Explanation:

Number of moles of NaOH solution having 17.5 gram NaOH in 350ml of water.

Atomic weight of NaOH = 40 g/mol

thus number of moles= 17.5/40

                                      =  0.437 moles

Now the molarity of the solution is calculated as

M=n/C

  = 0.437/O.35 LITRES

  = 1.248 M solution of the base

the molarity of acid is given as 0.25 M of HNO3

From the formula

M1V1=M2V2  we can calculate the volume of HNO3 required to make solution acidic.

1.248*350= 0.25*v2

v2=  1.248*350/0.25

     = 1747.2 ml

Thus 1747.2 ml of HNO3 is required.

3 0
3 years ago
Which two substances have no fixed shape and no fixed volume?
zalisa [80]

Answer:

Gases

Explanation:

4 0
4 years ago
To what extent are countries adapting to the effects of climate change, and why is adapting more challenging for some countries
Alika [10]

Answer:

Progress made in Asia and the Middle East is clear, with nations such as China, Singapore and Malaysia all demonstrating increased adaptability. Much of Africa has also made progress since 1995, along with South American nations, including Brazil and Chile.

5 0
3 years ago
Why doesn’t neon readily form an ionic bond?
Goryan [66]

By definition of noble gases, neon does not easily form an ionic bond because it belongs to the group of noble or inert gases, so its reactivity is practically nil.

<h3>Noble gases</h3>

Noble gases are not very reactive, that is, they practically do not form chemical compounds. This means that they do not react with other substances, nor do they even react between atoms of the same gas, as is the case with diatomic gases such as oxygen (O₂).

The chemical stability of the noble gases and therefore the absence of spontaneous evolution towards any other chemical form, implies that they are already in a state of maximum stability.

All chemical transformations involve valence electrons, they are involved in the process of covalent bond formation and the formation of ions. Therefore, the practically null reactivity of the noble gases is due to the fact that they have a complete valence shell, which gives them a low tendency to capture or release electrons.

Since the noble gases do not react with the other elements, they are also called inert gases.

<h3>Neon</h3>

Neon does not easily form an ionic bond because it belongs to the group of noble or inert gases, so its reactivity is practically nil.

Learn more about noble gases:

brainly.com/question/8361108

brainly.com/question/11960526

brainly.com/question/19024000

6 0
3 years ago
Read 2 more answers
A gas has a volume of 490. mL at a temperature of -35.0 degrees C. What volume would the gas occupy at 42.0 degrees Celsius? Ple
miskamm [114]

Answer:

648.5 mL

Explanation:

Here we will assume that the pressure of the gas is constant, since it is not given or specified.

Therefore, we can use Charle's law, which states that:

"For an ideal gas kept at constant pressure, the volume of the gas is proportional to its absolute temperature"

Mathematically:

\frac{V}{T}=const.

where

V is the volume of the gas

T is its absolute temperature

The equation can be rewritten as

\frac{V_1}{T_1}=\frac{V_2}{T_2}

where in this problem we have:

V_1=490 mL is the initial volume of the gas

T_1=-35.0^{\circ} + 273 = 238 K is the initial temperature

T_2=42.0^{\circ}+273=315 K is the final temperature

Solving for V2, we find the final volume of the gas:

V_2=\frac{V_1 T_2}{T_1}=\frac{(490)(315)}{238}=648.5 mL

8 0
4 years ago
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