Answer:
5. The mass of Na₂CO₃, that will produce 5 g of CO₂ is approximately 12.04 grams of Na₂CO₃
6. The mass of nitrogen gas (N₂) that will react completely with 150 g of hydrogen (H₂) in the production of NH₃ is 693.
grams of N₂
Explanation:
5. The given equation for the formation of carbon dioxide (CO₂) from sodium bicarbonate (Na₂CO₃) is presented as follows;
(Na₂CO₃) + 2HCl → 2NaCl + CO₂ + H₂O
One mole (105.99 g) of Na₂CO₃ produces 1 mole (44.01 g) of CO₂
The mass, 'x' g of Na₂CO₃, that will produce 5 g of CO₂ is given by the law of definite proportions as follows;
The mass of Na₂CO₃, that will produce 5 g of CO₂, x ≈ 12.04 g
6. The chemical equation for the reaction is presented as follows;
N₂ + 3H₂ → 2NH₃
Therefore, one mole (28.01 g) of nitrogen gas, (N₂), reacts with three moles (3 × 2.02 g) of hydrogen gas (H₂) to produce 2 moles of ammonia (NH₃)
The mass 'x' grams of nitrogen gas (N₂) that will react completely with150 g of hydrogen (H₂) in the production of NH₃ is given as follows;
The mass of nitrogen gas (N₂) that will react completely with 150 g of hydrogen (H₂) in the production of NH₃, x = 693. grams
Mass =70 ( Mass of protons=1 ,Mass of neutrons =1, Mass of electron =0.0005(can be ignored))
Therefore, 40 +30=70
Charge= -2 ( it is taking in/attracting electrons to its shell) base on the proton number you are able to identify if it is attracting or releasing an electron, if the electron number is more than proton number then it is attracting therefore resulting in a negative charge vice versa for releasing an electron.
1,771 millimeters are more than 1 meter :)
The reaction is spontaneous at high temperatures, and non-spontaneous at low temperatures.
In a thermodynamically closed system, the measure of the non-expansion work by the system and the enthalpy and the entropy is said to be the <u>Gibbs free energy</u>.
<h3>How to determine the Gibbs free energy?</h3>
According to the reaction, the enthalpy change 
and the change in the entropy 
is positive. The Gibbs free energy is given by, 
and the reaction will be spontaneous only when the 
is negative.
If there is not much effect on the enthalpy and entropy due to a decrease in temperature, then the value of the Gibbs free energy will be positive and will be close to that of the enthalpy change. In the above reaction enthalpy, change is positive and hence the reaction will be non-spontaneous.
When the temperature is increased then the entropy will affect the overall reaction as the Gibbs free energy will have the opposite sign as that of the entropy. So the reaction will become spontaneous at high temperatures.
Thus, option A is correct.
Learn more about Gibbs free energy here:
brainly.com/question/7988114
It means that they are bonded together
