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3 years ago

Which type of bond is between magnesium and oxygen?

2 answers:

5 0

Well magnesium has a negative charge and oxygen has a positive charge which makes them cancel out each other making it an ionic bond :)))))))<span />

TEA [102]3 years ago

4 0

Ionic bonding , because magnesium is a metal and oxygen is a non-metal .

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When the equation Al2(SO4)3 + NaOH + Al(OH)3 + Na2SO4 is correctly balanced, what is the coefficient of Al(OH)3?

nevsk [136]

The balanced chemical formula should be Al2(SO4)3 + 6NaOH = 2Al(OH)3 + 3Na2SO4

Therefore the coefficient of Al(OH)3 is 2!

Hope that helps :)

4 0

3 years ago

Which method of heat transfer takes place when particular of matter vibrate and collide with each other in direct contact?

Luden [163]

Conduction - by touch
Convection - hot air rises, cold air sinks
Insulation - to insulate or capture heat
Radiation - by waves
Direct contact means touch, therefore the answer would be conduction.

5 0

3 years ago

Read 2 more answers

Of the following gases which will have the lowest rate of effusion at a given temperature?A. SO3B. CH4C. NH3D. HBr E. HCl

egoroff_w [7]

Answer: HBr has the lowest rate of effusion at a given temperature.

Explanation: The effusion rate usually increases with increase in temperature because the kinetic energy of the gaseous molecules increases. But it was not true for gases having heavier mass. This was explained by Graham's Law.

Graham's Law states that the rate of effusion of a gas is inversely proportional to the square root of its molecular weight.

$(\text{Rate of effusion})_A\propto \frac{1}{\sqrt{\text{Mol. mass}_A}}$

We are given different gases with different Molecular masses. The gas having larger Molecular mass will have the lowest rate of effusion.

Mol. Mass of $SO_3$ = 80 g/mol

Mol. Mass of $CH_4$ = 16 g/mol

Mol. Mass of $NH_3$ = 17 g/mol

Mol. Mass of HBr = 81 g/mol

Mol. Mass of HCl = 36 g/mol

As, Mol. mass of HBr is the highest, so its rate of effusion will be the lowest.

6 0

3 years ago

What is a substance made of 2 or more elements called

Wittaler [7]

It’s called a compound

7 0

3 years ago

Read 2 more answers

The combustion of methane is a reaction commonly used in chemistry problems due to its ability to fit into multiple topics. So i

lyudmila [28]

Answer:

20.76 L OF CO2 WILL BE PRODUCED BY 45 G OF METHANE.

Explanation:

Equation of the reaction:

CH4 + 02 --------> CO2 + 2H20

Molar mass of methane = ( 12+ 1*4) g/mol = 16 g/mol

Calculate the number of moles present in 45 g of methane

1 mole of methane = 16 g / mol of methane

(45 / 16) mole of methane = 45 g of methane

= 2.8125 moles

Using the ideal gas equation:

PV = nRT

P = 1 atm

n = 2.812 moles

T = 90 C

R = 0.082 L atm/ mol C

V = unknown

So we have:

V = nRT / P

V = 2.8125 * 0.082 * 90 / 1

V = 20.756 L

In the production of CO2 by 45 g of methane, 20.756 L of methane was used.

Then, the volume of CO2 produced by this volume will be 20.756 L since 1 mole of methane produces 1 mole of CO2.

In other words;

1 mole of CH4 = 1 mole of CO2

22.4 dm3 of CH4 = 22.4 dm3 of CO2

20.76 DM3 = 20.76 dm3

The volume of CO2 produced will therefore be 20.76 L

8 0

3 years ago