Force = (mass) x (acceleration).
We know the force and the mass, so we can write
6,000 N = (1,200 kg) x (acceleration).
Divide each side by 1,200 kg:
Acceleration = 6000N/1200kg = 5 m/s² .
That's the acceleration. The car's speed changes by 5 m/s each second
that the force acts on it. If the force pushes from behind, then the car goes
5 m/s faster every second. If the force pushes from in front, then the car
goes 5 m/s slower every second.
The car is moving at 10 m/s and we want to slow it down to zero m/s. So
the force has to push from the front, and it will take (10/5) = <em>2 seconds</em> to
complete the job.
Answer:option C
Explanation:
Angular momentum equal to radius times linear momentum
So ang momentum equal to
1 meter x (MV)
1 m x (1.25 kg x 180 m/s)
225 kg m square/second
Hence option C
30 grams of radioactive isotope have passed.
Answer:
its a shield that can protect us from super hot rays and all though ita not that strong atleast we wont get burned to death lol :)
Answer:
The third polarizer can be placed midway between the first two polarizers with its extinction axis at 45° from either polarizer to maximize the amount of light that is transmitted (one-eight).
Explanation:
If light is incident on a polarizer, it allows only light that is parallel to its 'pass-through' axis to pass through untouched.
Light whose electric direction/vector is perpendicular to the 'pass through' axis will not pass through at all. Light whose electric direction/vector points in other directions (apart from those whose direction is parallel or perpendicular) passes through according to the magnitude of the component that is parallel to the 'pass-through' axis.
The polarizer blocks half of the incident light rays and the transmitted light is polarized in the direction of the 'pass-through' axis.
A new polarizer now place at a distance from the first polarizer with its 'pass-through' axis perpendicular to the first polarizer cancel out all the light that comes through from the first polarizer. Since the light electric vector needs to be parallel to the axis of the polarizer to pass through and all the parallelized light from the first polarizer are now incident perpendicularly to the axis of the second polarizer, no light rays pass through.
But, a third polarizer can be placed midway between the first two polarizers with its axis positioned at 45° from either polarizer. Thereby allowing exactly half of the light from the first polarizer to pass through. The explanation is just like that for the first one. (Light whose electric direction/vector points in other directions (apart from those whose direction is parallel or perpendicular) passes through according to the magnitude of the component that is parallel to the 'pass-through' axis).
Then the resultant from the middle polarizer reaches the initial second polarizer and half of the light is let through again. So that, at the end of the day, (1/2) × (1/2) × (1/2) of the initial incident ray is let through.
That is, to maximize the amount of light that is transmitted (one-eight of initial incident ray) the third Polaroid is place midway between the first two and at angle 45° to either one.
