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Oksi-84 [34.3K]
3 years ago
7

The tires of a car support the weight of a stationary car. If one tire has a slow leak, the air pressure within the tire will __

_____ with time, the surface area between the tire and the road will _______ with time, and the net force the tire exerts on the road will _______ with time.a) Increase, Increase, Increase
b) Decrease, decrease, decrease
c) Decrease. increase,increase
d) Decrease, increase, remain constant
e) Decrease, increase, decrease
Physics
1 answer:
mrs_skeptik [129]3 years ago
8 0

Answer:

The answer is E. Decrease, increase, decrease

Explanation:

The pressure within the tire wall is a result of the molecules of air colliding with the walls of the tire, if there is a leakage that means some or all of the air molecules will escape resulting in a decrease in the collision between the molecules and the tire wall which means the pressure decreases within the walls which also translates to a decrease in pressure exerted by the tire on the ground surface.

Before the leakage, the tire walls are kept tensed due to the internal pressure exerted by the air molecules. When the leakage occurs the air molecules escape and this makes the tire loose its firm upright shape thereby falling to the floor and creating an increase in the area of contact between the tire and the floor surface.

The force exerted on the floor by the tire is proportional to the the pressure exerted and the surface area through which this force is applied, though the pressure is seen to decrease and the surface area seen to increase, one must consider the weight loss due to the air molecules that escapes which causes the force to decrease.

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The magnitude of a vector can be different in different coordinate systems. The magnitude of a vector can be different in differ
Georgia [21]

Answer:

False.

Explanation:

We usually define vectors in terms of its magnitude and their orientation. Magnitude and direction does not vary with the change of a coordinate system as they are independent of coordinates and will remain the same. So it does not matter what your choice of a coordinate system is, it will not effect its direction and magnitude. However you can resolve the vector in to its components if you want.

4 0
3 years ago
What is the relationship between temperature and peak wavelength?
Zepler [3.9K]
The correct option is B.
All objects emit electromagnetic radiation and the amount of radiation emitted at each wavelength depend on the temperature of the object. This observation is described by Wien's law, which states that the black body radiation curve for different temperatures peaks at a wavelength that is inversely proportional to the temperature. 
5 0
3 years ago
A cylinder containing an ideal gas has a volume of 2.6 m3 and a pressure of 1.5 × 105 Pa at a temperature of 300 K. The cylinder
frozen [14]
<h2>Answer:13.5\times 10^{8} joules</h2>

Explanation:

From the first law of thermodynamics,

ΔQ=ΔU+W

Where Q is the heat given to the gas,

U is the internal energy of the gas,

W is the workdone by the gas.

When pressure is constant,

\frac{V_{1}}{T_{1}}=\frac{V_{2}}{T_{2}}

V_{2}=\frac{2.6\times 900}{300}=7.8m^{3}

When pressure is constant,W=PΔV

Where P is pressure and V is the volume of the gas.

Given P=1.5\times 10^{5}Pa

ΔV=7.8-2.6=5.2m^{3}

So,W=1.5\times 10^{5}\times 5.2=7.8\times 10^{5}J

Given that ΔU=6\times 10^{5}

So,ΔQ=6\times 10^{5}+7.8\times 10^{5}=13.8\times 10^{5}J

5 0
4 years ago
Calculate the de Broglie wavelength of: a) A person running across the room (assume 180 kg at 1 m/s) b) A 5.0 MeV proton
solmaris [256]

Answer:

a

\lambda = 3.68 *10^{-36} \  m

b

\lambda_p = 1.28*10^{-14} \ m

Explanation:

From the question we are told that

   The mass of the person is  m =  180 \  kg

    The speed of the person is  v  =  1 \  m/s

    The energy of the proton is  E_ p =  5 MeV = 5 *10^{6} eV  = 5.0 *10^6 * 1.60 *10^{-19} = 8.0 *10^{-13} \  J

Generally the de Broglie wavelength is mathematically represented as

      \lambda = \frac{h}{m * v }

Here  h is the Planck constant with the value

      h = 6.62607015 * 10^{-34} J \cdot s

So  

     \lambda = \frac{6.62607015 * 10^{-34}}{ 180  * 1  }

=> \lambda = 3.68 *10^{-36} \  m

Generally the energy of the proton is mathematically represented as

         E_p =  \frac{1}{2}  *   m_p  *  v^2_p

Here m_p  is the mass of proton with value  m_p  =  1.67 *10^{-27} \  kg

=>     8.0*10^{-13} =  \frac{1}{2}  *   1.67 *10^{-27}  *  v^2

=>   v _p= \sqrt{\frac{8.0 *10^{-13}}{ 0.5 * 1.67 *10^{-27}} }

=>   v = 3.09529 *10^{7} \  m/s

So

        \lambda_p = \frac{h}{m_p * v_p }

so    \lambda_p = \frac{6.62607015 * 10^{-34}}{1.67 *10^{-27} * 3.09529 *10^{7} }

=>     \lambda_p = 1.28*10^{-14} \ m

     

5 0
3 years ago
58.5 million excess electrons are inside a closed surface. What is the net electric flux through the surface?
Anni [7]
The biggest thing you're doing wrong is ignoring the units
when you're working with the quantities.

Now let's look at the rest of the problem:

The formula you used is correct:

           Net flux through the surface = (net charge inside) / ε₀

and          ε₀ = 8.85 x 10⁻¹² farad/meter.

What's the net charge inside the surface in this problem ?

It's    (5.85 x 10⁷ electrons) x (the charge on each electron)

     =  (5.85 x 10⁷ electrons) x (-1.6 x 10⁻¹⁹ coulomb/electron)

     =      -9.36 x 10⁻¹² coulomb .   

Finally,      (net charge inside) / ε₀

             =  (-9.36 x 10⁻¹² coulomb) / (8.85 x 10⁻¹² farad/meter)

             =        -1.058  newton-m²/coulomb .

The sign and the significant figures in your answer are correct, so
we can see that you know what you're doing.  The only thing left is
the order of magnitude.  You most likely took one of the negative
exponents and made it positive.  You got an answer that's 10²² too
small.  Big deal.  You could claim "that's close", and see whether you
can convince a teacher.
8 0
3 years ago
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