Answer:
Explanation:
To get the person Moving you have to overcome the static (means not moving) friction coefficient. U(static)
To get the person going at the same speed you have to overcome the kinetic friction coefficient. U(Kinetic)
Force to get him moving is 198 N. Force = ma = U(static)Mg
combining the 2 equations you get 198N = U(static)* 55kg *9.8m/s^2 Solve for U(static)
Same equation to keep him moving except with the dynamic force and the dynamic U
175N= U(kinetic)*55kg*9.8m/s^2 Solve (U dynamic)
Answer:
speed = 3.95 m/s
Explanation:
area = π x radius^2
area = π x (2.67 x 10^-3)^2
volume flow rate = area x speed
volume / time = area x speed
density = mass / volume
volume = mass / density
<u>mass / (density x time) = area *speed</u>
mass flow rate = mass / time
<u>mass flow rate / density = area x speed</u>
6.55 x 10^-2 / 740 = pi * (2.67 x 10^-3)^2 * speed
speed =8.8514 x 10-5 /2.2396 x 10-5 m/s
speed = 3.95 m/s
Answer:
What is a Free Body Diagram?
The free body diagram helps you understand and solve static and dynamic problem involving forces. It is a diagram including all forces acting on a given object without the other object in the system. You need to first understand all the forces acting on the object and then represent these force by arrows in the direction of the force to be drawn.
Explanation:
Answer:
The velocity is 31.25 m/s and direction is toward west.
Explanation:
Given that,
Distance 
Magnetic field 
Mass of proton 
Radius of earth 
Radius of orbit 
We need to calculate the speed
Using formula of magnetic field
Put the value into the formula
Hence, The velocity is 31.25 m/s and direction is toward west.
Answer:
I = 8.75 kg m
Explanation:
This is a rotational movement exercise, let's start with kinetic energy
K = ½ I w²
They tell us that K = 330 J, let's find the angular velocity with kinematics
w² = w₀² + 2 α θ
as part of rest w₀ = 0
w = √ 2α θ
let's reduce the revolutions to the SI system
θ = 30.0 rev (2π rad / 1 rev) = 60π rad
let's calculate the angular velocity
w = √(2 0.200 60π)
w = 8.683 rad / s
we clear from the first equation
I = 2K / w²
let's calculate
I = 2 330 / 8,683²
I = 8.75 kg m
