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3 years ago

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The Sun is the largest object in our (1) _ . Its (2) _ controls the motions of the plane

ts. The center of the Sun is very dense. The high temperature at its center causes the solar interior to be (3) ______________

1 answer:

777dan777 [17]3 years ago

7 0

Answer:

1. solar system

2. gravity

3. brightest

Explanation:

i am not sure for 3 part but 1 and 2 are correct

OK

hope it helps

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As a hiker in Glacier National Park, you are looking for a way to keep the bears from getting at your supply of food. You find a

Lorico [155]

Answer:

Acceleration of the bags is 0.861 m/s²

Explanation:

Given:

Mass of the rock, m = 22.5 kg = mass of the food

Slope, Θ = 55.5°

Now, from the figure, we have

T - mgsinΘ = ma ...................(1)

'a' is the acceleration of the mass

where T is the tension

also for the second mass, we have

mg - T = ma

now substituting the value of T from the equation (1) we get

mg - (ma + mgsinΘ) = ma

or

mg(1 - sinΘ) = (m + m)a

or

a = $\frac{mg(1 - sin\theta)}{2m}$

on substituting the values we get

a = $\frac{9.8\times (1 - sin55.5^o)}{2}$

or

a = 0.861 m/s²

Hence, the acceleration of the bags is 0.861 m/s²

7 0

3 years ago

device for heating a cup of water in a car connects to the car's battery, which has an emf E = 10.0 V and an internal resistance

tatuchka [14]

Answer:

R = 0.93 ohms

Explanation:

Let's start by calculating the resistance of the coil,

V = I ( R + r )

Make R the subject of the above equation.

Hence,

V = IR + Ir

V - Ir = IR

( V - Ir )/I = R

Given that V = 10V

r = 0.07ohms

I = 10A ( this is an assumption )

( 10 - 10×0.07 ) ÷ 10

R = 0.93 ohms

Note: r is the internal resistance, R is the resistance, I is the current and the emf is represented as V. Since current was supposed to be included in the question but it was not, hence it was assumed to be 10A . Meaning whatsoever value is given for current will be substituted into the equation. Thanks

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A fish swimming in a horizontal plane has velocity i = (4.00 î + 1.00 ĵ) m/s at a point in the ocean where the position relative

Liula [17]

Question is missing. Found on google:

a) What are the components of the acceleration of the fish?

(b) What is the direction of its acceleration with respect to unit vector î?

(c) If the fish maintains constant acceleration, where is it at t = 30.0 s?

(a) $(0.73, -0.47) m/s^2$

The initial velocity of the fish is

$u=(4.00 i + 1.00 j) m/s$

while the final velocity is

$v=(15.0 i - 6.00 j) m/s$

Initial and final velocity are related by the following suvat equation:

$v=u+at$

where

a is the acceleration

t is the time

The time in this case is t = 15.0 s, so we can use the previous equation to find the acceleration, separating the components:

$v_x = u_x + a_x t\\a_x = \frac{v_x-u_x}{t}=\frac{15.0-4.00}{15.0}=0.73 m/s^2$

$v_y = u_y + a_y t\\a_y = \frac{v_y-u_y}{t}=\frac{-6.00-1.00}{15.0}=-0.47 m/s^2$

(b) $-32.8^{\circ}$

The direction of the acceleration vector with respect to i can be found by using the formula

$\theta = tan^{-1}(\frac{a_y}{a_x})$

where

$a_x$ is the horizontal component of the acceleration

$a_y$ is the vertical component of the acceleration

From part a), we have

$a_x = 0.73 m/s^2$

$a_y = -0.47 m/s^2$

Substituting,

$\theta = tan^{-1}(\frac{-0.47}{0.73})=-32.8^{\circ}$

(c) $r=(460.5 i - 185.1 j )m$

The initial position of the fish is

$r_0 = (12.0 i -3.60 j) m$

The generic position r at time t is given by

$r= r_0 + ut + \frac{1}{2}at^2$

where

$u=(4.00 i + 1.00 j) m/s$ is the initial velocity

$a=(0.73 i -0.47 j) m/s^2$ is the acceleration

Substituting t = 30.0 s, we find the final position of the fish. Separating each component:

$r_x =12.0 + (4.00)(30) + \frac{1}{2}(0.73)(30)^2=460.5 m\\r_y = -3.60 + (1.00)(30) + \frac{1}{2}(-0.47)(30)^2=-185.1 m$

So the final position is

$r=(460.5 i - 185.1 j )m$

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Which of the following statements about the electromagnetic spectrum is true?

Andre45 [30]

Answer:

B. its consist of waves of varying lengtu

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Genrish500 [490]

Answer:

Steam engines to operate using only hot steam

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