False you cant control the size of feet
Explanation:
Answer
( 58.3 mL ) (
0.789 g
1 mL
) (
1 mole
46 g
) = 1 mole C2H5OH
( 500 mL H2O ) (
1 g
1 mL
) (
1 mole
18 g
) = 27.8 mole H2O
The total moles = 1 mole C2H5OH + 27.8 mole H2O = 28.8 moles
The mole fraction =
moles C2H5OH
total moles
=
1 mole C2H5OH
28.8 total moles
= 0.035
The mole percent would be 3.5%.
What is the weight fraction?
Answer
( 58.3 mL ) (
0.789 g
1 mL
) = 46 g C2H5OH
( 500 mL H2O ) (
1 g
1 mL
) = 500 g H2O
The total mass = 46 g C2H5OH + 500 g H2O = 546 g
The mass fraction =
mass C2H5OH
total mass
=
46 g C2H5OH
546 total grams
= 0.084
The mass percent would be 8.4%.
What is the molarity?
Answer
The molarity =
moles C2H5OH
L of solution
=
1 mole C2H5OH
.5583 L
= 1.79 M
What is the molality?
Answer
The molality =
moles C2H5OH
kg of solvent
=
1 mole C2H5OH
0.5 kg H2O
= 2
Ground state, since electrons want to be in the lowest energy position as possible, which is closer to the nucleus of the atom.
Answer: C REFRACTION
Explanation: I took the test and got it right lol <3
<u>Answer:</u> The specific heat of ice is 2.11 J/g°C
<u>Explanation:</u>
When ice is mixed with water, the amount of heat released by water will be equal to the amount of heat absorbed by ice.
The equation used to calculate heat released or absorbed follows:
![m_1\times c_1\times (T_{final}-T_1)=-[m_2\times c_2\times (T_{final}-T_2)]](https://tex.z-dn.net/?f=m_1%5Ctimes%20c_1%5Ctimes%20%28T_%7Bfinal%7D-T_1%29%3D-%5Bm_2%5Ctimes%20c_2%5Ctimes%20%28T_%7Bfinal%7D-T_2%29%5D)
......(1)
where,
q = heat absorbed or released
= mass of ice = 12.5 g
= mass of water = 85.0 g
= final temperature = 22.24°C
= initial temperature of ice = -15.00°C
= initial temperature of water = 25.00°C
= specific heat of ice = ?
= specific heat of water = 4.186 J/g°C
Putting values in equation 1, we get:
![12.5\times c_1\times (22.24-(-15))=-[85.0\times 4.186\times (22.24-25)]](https://tex.z-dn.net/?f=12.5%5Ctimes%20c_1%5Ctimes%20%2822.24-%28-15%29%29%3D-%5B85.0%5Ctimes%204.186%5Ctimes%20%2822.24-25%29%5D)
Hence, the specific heat of ice is 2.11 J/g°C
