T is amount after time t
<span>Ao is initial amount </span>
<span>t is time </span>
<span>HL is half life </span>
<span>log (At) = log [ Ao x (1/2)^(t/HL) ] </span>
<span>log (At) = log Ao + log (1/2)^(t/HL) </span>
<span>log (At) = log Ao + (t/HL) x log (1/2) </span>
<span>( log At - log Ao) / log (1/2) = t / HL </span>
<span>log (At/Ao) / log (1/2) = t / HL </span>
<span>HL = t / [( log (At / Ao)) / log (1/2) ] </span>
<span>HL = 14.4 s / [ ( log (12.5 / 50) / log (1/2) ] </span>
<span>HL = 14.4 s / 2 = 7.2 seconds </span>
Answer: ⚫⚫⚫⚫⚫⚫⚫⚫⚫⚫⚫⚫⚫⚫⚫⚫⚫⚫⚫⚫⚫⚫⚫⚫⚫⚫⚫⚫⚫⚫⚫⚫⚫⚫⚫⚫⚫⚫⚫⚫⚫⚫⚫⚫⚫⚫⚫⚫⚫⚫⚫⚫⚫⚫
Explanation:
Assuming that the O2 gas acts like an ideal gas, we find
the following expression to be approximates of the behaviour of this gas:
<span>P V = n R T --->
1</span>
where,
P = pressure exerted by the gas
V = volume occupied
n = number of moles
R = universal gas constant
T = absolute temperature
Further, we assume that the number of moles and the
temperature are constant, hence reducing equation 1 into the form:
<span>P V = k --->
2</span>
where k is a constant. Therefore we can equate two
states:
P1 V1 = P2 V2
Since P1, V1 and V2 are given and we are to look for P2:
25 mL * 2 atm = 100 mL * P2
<span>P2 = 0.5 atm</span>
<h2>♨ANSWER♥</h2>
pl (25*C)
Arginine -----> 10.76
Glutamic -----> 3.08
Asparagine -----> 5.43
Tyrosine -----> 5.63
<u>☆</u><u>.</u><u>.</u><u>.</u><u>hope this helps</u><u>.</u><u>.</u><u>.</u><u>☆</u>
_♡_<em>mashi</em>_♡_
It is the work of J.J Thomson that directly resulted in the development of an atomic model that has negative electrons stuck within a sea of positive material. His proposal was called the plum pludding model. He is the one who discovered electrons.
