All categories

3 years ago

Imagine an object falling to the Earth. Which of the following most accurately describes the motion of that object?

Chemistry

2 answers:

Lena [83]3 years ago

7 0

Gravity is pulling it toward the earth, as it would have kinetic energy since it is in motion.

andre [41]3 years ago

3 0

Answer:

it falls towrd the center of the earth

Explanation:

the earth doesnt have gravity like space

You might be interested in

Practice entering numbers that include a power of 10 by entering the diameter of a hydrogen atom in its ground state, dH=1.06×10

kkurt [141]

Answer:

The diameter of the hydrogen $\mathbf{d =1.0605 \times 10^{-10}\ m}$

Explanation:

From the given information:

Using the concept of Bohr's Model, the equation for the angular momentum can be expressed as:

$L = \dfrac{nh}{2 \pi}$

Where the generic expression for angular momentum is:

L = mvr.

replacing the value of L into the previous equation, we have:

$mvr= \dfrac{nh}{2 \pi}$

$v= \dfrac{nh}{2 \pi mr}$ ----- (1)

The electron in the hydrogen atom posses an electrostatic force which gives a centripetal force.

$\dfrac{ke^2}{r^2} = \dfrac{mv^2}{r}$ ----- (2)

replacing the value of v in equation (1) into (2), and taking r as the subject of the formula, we have:

$\dfrac{ke^2}{r} = m (\dfrac{nh}{2 \pi mr})^2$

$ke^2=\dfrac{n^2h^2}{4 \pi^2 mr}$

$r =\dfrac{n^2h^2}{4 \pi^2 mke^2}$

For ground-state n = 1

$h = (6.625 \times 10^{-34} \ J.s)^2$

$m =( 9.1 \times 10^{-31} \ kg)(9 \times 10^9 \ N .m^2/C^2)$

$Ke = (1.6 \times 10^{-19} \ C)^2$

$r =\dfrac{(1)^2(6.625 \times 10^{-34})^2}{4 \pi^2 (9.1 \times 10^{-31} )(9 \times 10^9 ) (1.6 \times 10^{-19})^2}$

$r =\dfrac{4.3890625 \times 10^{-67}}{8.27720295 \times 10^{-57}}$

$\mathbf{r = 5.3025 \times 10^{-11} \ m}$

Therefore, the diameter of hydrogen d = 2r

$\mathbf{d = ( 2 \times 5.3025 \times 10^{-11} \ m})}$

$\mathbf{d =1.0605 \times 10^{-10}\ m}}$

4 0

3 years ago

You see the middle layer of the sun’s atmosphere, the _____________, at the start and end of a total eclipse.

Helen [10]

Answer:

Chromosphere

Explanation:

You see the middle layer of the sun’s atmosphere, the Chromosphere, at the start and end of a total eclipse.

4 0

3 years ago

What mass of cu(s)cu(s) is electroplated by running 14. 5 aa of current through a cu2 (aq)cu2 (aq) solution for 4. 00 hh?

galina1969 [7]

The mass of Copper electroplated is 68.76 g

<h3>What is electroplating?</h3>

The process of plating a metal onto another is known as electroplating.

It is often used to prevent corrosion of metal or for the decorative purposes

In this process, electric current is passed through an aqueous solution containing dissolved cations.

The dissolved cations are reduced developing a thin metal coating on the electrode.

At cathode,

$Cu^{2+}(aq) + 2e^-\rightarrow Cu(s)$

Current, I = 14.5 A

Time, t = 4 hrs = 4×60×60 = 14400 sec

Charge, q = It = 14.5×14400= 208800 C

Copper metal deposited by 2×96487 C = 63.55 g

Copper metal deposited by 208800 C = $\frac{63.55 \times208800}{2\times96487}$

= 68.76g

Hence, The mass of Copper electroplated is 68.76 g

Learn more about electroplating:

brainly.com/question/22104403

#SPJ4

4 0

1 year ago

Read 2 more answers

Which word is used describe someone who is fair and has no bias?

rodikova [14]

Impartial is the word that you want to use

6 0

3 years ago

Read 2 more answers

Jane was drinking a glass of water. She asked her father where the water

Rzqust [24]

Janes brother Jack is actually correct, underground water seeps into little holes or spaces between the soil and the rocks.

<h3>Underground Water</h3>

Simply put, underground water is found in between soils and crack, another name for this is called aquifers were water is found.

It should be noted that underground water are found at varying levels depending the terrain.

Learn more about Underground Water here:

brainly.com/question/23135301

5 0

2 years ago