1answer.
Ask question
Login Signup
Ask question
All categories
  • English
  • Mathematics
  • Social Studies
  • Business
  • History
  • Health
  • Geography
  • Biology
  • Physics
  • Chemistry
  • Computers and Technology
  • Arts
  • World Languages
  • Spanish
  • French
  • German
  • Advanced Placement (AP)
  • SAT
  • Medicine
  • Law
  • Engineering
Sati [7]
2 years ago
7

What is the concentration of OH− in a solution with a pOH value of 6.09

Chemistry
1 answer:
djyliett [7]2 years ago
5 0

Answer:

I'm not sure

Explanation:

I'm just not sure

You might be interested in
The number of molecules in 1.0 mole of H2O is the same as in one mole of O2.
zaharov [31]
True. A mole of anything has the same amount of molecules. 1 mole = 6.022 x 1023 molecules 
8 0
3 years ago
Read 2 more answers
Materials Science is the study of solid stuff.<br>A True<br>B) False​
miv72 [106K]

Answer:

true

Explanation:

Materials science is an interdisciplinary field involving the properties of matter and its applications to various areas of science and engineering. It includes elements of applied physics and chemistry, as well as chemical, mechanical, civil and electrical engineering.

and we all know matter involve solid liquid or gas

7 0
3 years ago
Read 2 more answers
Cho 6,72 gam Fe tan hết trong dung dịch H2SO4 đặc nóng dư thu được V lít khí SO2. Giá trị của V là
g100num [7]

4,032

BT electron

nSO2= 3nFe/

8 0
2 years ago
GIVING BRAINLIEST!!! A student observes a beaker of room temperature water resting on a table. She states that the beaker of wat
defon

Answer:

a

Explanation:

im thinking because the water is a room temperature there shouldnt be anm immence amount og heat energy for it to have a good amount of energy tho i could be wrong because its not moving it could have no energy.

8 0
3 years ago
Read 2 more answers
25 points please help
maxonik [38]

Answer : Option (A) Accelerator 2 model has the lowest percentage of energy lost as waste.

Solution : Given,

For Accelerator 1 model,

Input energy = 2078.3 J

Wasted energy = 663.1 J

Output energy = 1415.2 J

For Accelerator 2 model,

Input energy = 7690.0 J

Wasted energy = 2337.5 J

Output energy = 5353.5 J

For Accelerator 3 model,

Input energy = 4061.9 J

Wasted energy = 2259.6 J

Output energy = 1802.3 J

Formula used for lowest percentage of energy lost as waste is:

% energy lost as waste = (Total energy wasted / Total input energy )  ×  100

For Accelerator 1 model,

% energy lost as waste = \frac{663.1}{2078.3}\times100 = 31.90%

For Accelerator 2 model,

% energy lost as waste = \frac{2337.5}{7690.0}\times100 = 30.39%

For Accelerator 3 model,

% energy lost as waste = \frac{2259.6}{4061.9}\times100 = 55.62%

So, we conclude that the Accelerator 2 model has the lowest percentage of energy lost as waste.



6 0
3 years ago
Other questions:
  • A 0.8838-g sample of an ionic compound containing bromide ions and an unknown metal cation is dissolved in water and treated wit
    8·2 answers
  • Metals are used in many products because of the characteristic properties that most metals have. Which product requires the high
    13·2 answers
  • What physical property makes metal pot good for cooking
    7·1 answer
  • suppose you wanted to change the rate of a chemical reaction. what might you change in the reaction? explain the factor
    13·1 answer
  • PLEASE ANSWER
    7·1 answer
  • How many molecules are in 9.95 moles of Co2?
    15·1 answer
  • Select the correct answer. Which substance is made of polymers? A. marble B. protein C. salt D. steel
    9·2 answers
  • In 1774, Joseph Priestly discovered oxygen gas by heating mercury(II) oxide powder with focused sunlight through a lens. How man
    7·1 answer
  • Activity/Exercises: Kobe has been living in a coastal barangay for 30 years. Recently, he noticed that during high tides, water
    13·1 answer
  • In an experiment, you measure a solution absorbance of 0.2 with a path length of 1cm. If the molar absorptivity coefficient is 5
    14·1 answer
Add answer
Login
Not registered? Fast signup
Signup
Login Signup
Ask question!