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3 years ago

There are 15 students going on a field trip. If 3/5 of them pack there lunches, how many students pack their lunches?

Mathematics

1 answer:

valentinak56 [21]3 years ago

6 0

Answer:

9 pack their lunches

Step-by-step explanation:

Take the number of students and multiply by the fraction that pack their lunches

15 *3/5 =

15/5 * 3

3*3

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What are like terms? Provide an example with your description. Choose the correct answer below. A. Like terms are terms that ha

ExtremeBDS [4]

Answer:

Option C.

Step-by-step explanation:

We need to find the correct definition of like terms.

Like terms :Two or more terms are called like terms if they have the same variables and same powers.

For example : 4xy and 9xy are like terms.

Option A is incorrect because 3x and 3 are not like terms.

Option B is incorrect because 6x and 9 are not like terms.

Option C is correct because like terms are terms that have the same variable factors as well as the same number of factors of each type. For example, 3x and 5x are like terms.

Option D is incorrect because 3x and 5 are not like terms.

Therefore, the correct option is C.

8 0

3 years ago

7. If the volume of a cylinder, where the height is 3 times the radius, is 247, find the surface area of the cylinder.

lakkis [162]

Answer:

3.87987×10^5

Step-by-step explanation:

surface area of the cylinder =2πrh+2πr²

=2*π*247*3+2*π*(247)²

=3.87987×10^5

7 0

3 years ago

This season, the probability that the Yankees will win a game is 0.49 and the probability that the Yankees will score 5 or more

yanalaym [24]

Answer:

0.226 = 22.6% probability that the Yankees will lose when they score 5 or more runs

Step-by-step explanation:

Conditional probability:

We use the conditional probability formula to solve this question. It is

In which

P(B|A) is the probability of event B happening, given that A happened.

is the probability of both A and B happening.

P(A) is the probability of A happening.

In this question:

If the Yankees score 5 or more runs, either they win, or they lose. The sum of these probabilities is 1.

Probability that the Yankees win:

Event A: Scoring 5 or more runs.

Event B: Winning

The probability that the Yankees will score 5 or more runs in a game is 0.53.

This means that

The probability that the Yankees win and score 5 or more runs is 0.41.

This means that

0.774 probability that the Yankees will win when they score 5 or more runs

What is the probability that the Yankees will lose when they score 5 or more runs?

p + 0.774 = 1

p = 1 - 0.774

p = 0.226

0.226 = 22.6% probability that the Yankees will lose when they score 5 or more runs

4 0

3 years ago

In a linear Pair angles are?

tatiyna

Answer:

angles in linear pair are 90° hope it helps u ♥♥♥♥♥♥♥

5 0

3 years ago

Read 2 more answers

In a certain Algebra 2 class of 30 students, 19 of them play basketball and 12 of them play baseball. There are 8 students who p

Alenkinab [10]

Answer:

Probability that a student chosen randomly from the class plays basketball or baseball is $\frac{23}{30}$ or 0.76

Step-by-step explanation:

Given:

Total number of students in the class = 30

Number of students who plays basket ball = 19

Number of students who plays base ball = 12

Number of students who plays base both the games = 8

To find:

Probability that a student chosen randomly from the class plays basketball or baseball=?

Solution:

$P(A \cup B)=P(A)+P(B)-P(A \cap B)$ ---------------(1)

where

P(A) = Probability of choosing a student playing basket ball

P(B) = Probability of choosing a student playing base ball

P(A \cap B) = Probability of choosing a student playing both the games

Finding P(A)

P(A) = $\frac{\text { Number of students playing basket ball }}{\text{Total number of students}}$

P(A) = $\frac{19}{30}$ --------------------------(2)

Finding P(B)

P(B) = $\frac{\text { Number of students playing baseball }}{\text{Total number of students}}$

P(B) = $\frac{12}{30}$ ---------------------------(3)

Finding $P(A \cap B)$

P(A) = $\frac{\text { Number of students playing both games }}{\text{Total number of students}}$

P(A) = $\frac{8}{30}$ -----------------------------(4)

Now substituting (2), (3) , (4) in (1), we get

$P(A \cup B)= \frac{19}{30} + \frac{12}{30} -\frac{8}{30}$

$P(A \cup B)= \frac{31}{30} -\frac{8}{30}$

$P(A \cup B)= \frac{23}{30}$

7 0

3 years ago