We need the following to be true
a+2b = -a
a+4 = 2a - 3b
Let's look at the first equation.
a + 2b = -a
Subtract both sides by a
2b = -2a
b = -a
Substitute b= -a into the second equation
a+4 = 2a + 3a
a + 4 = 5a
4a = 4
a = 1
Just take the negative of that and you get the value of b.
b = -1
Your solution is a=1 and b = -1.
Have an awesome day! :)
The answer is no. Because solution (a,b) means x=a, y=b.and we have a-b=5. And (b,a) would mean x=b and y=a but then x-y=b-a=-(a-b)=-5≠5. So the pair (b,a) is not a solution.
Answer:
-16
Step-by-step explanation:
f(x)=-8x+8 and g(x) = sqrt x-9
(f•g)(18)=f(g(18))
g(18)=sqrt(18-9)=sqrt9=3
f(3)=-24+8=-16
Answer:
y ≈ 5.63
Step-by-step explanation:
m∠KLN and m∠NLM have to add up to m∠KLM
m∠KLN = 47°
m∠NLM = 16y°
m∠KLM = 137°
47 + 16y = 137
16y = 90
y = 45/8
y = 5.625
y ≈ 5.63
We know that
case 1)
Applying the law of sines
a/Sin A=b/Sin B
A=56°
a=12
b=14
so
a*Sin B=b*Sin A----> Sin B=b*Sin A/a---> Sin B=14*Sin 56°/12
Sin B=0.9672
B=arc sin (0.9672)------> B=75.29°-----> B=75.3°
find angle C
A+B+C=180°-----> C=180-(A+B)----> C=180-(56+75.3)----> C=48.7°
find c
a/Sin A=c/Sin C----> c=a*Sin C/Sin A----> c=12*Sin 48.7°/Sin 56°)
c=10.87-----> c=10.9
the answer Part 1)
the dimensions of the triangle N 1
are
a=12 A=56°
b=14 B=75.3°
c=10.9 C=48.7°
case 2)
A=56°
a=12
b=14
B=180-75.3----> B=104.7°
find angle C
A+B+C=180°-----> C=180-(A+B)----> C=180-(56+104.7)----> C=19.3°
find c
a/Sin A=c/Sin C----> c=a*Sin C/Sin A----> c=12*Sin 19.3°/Sin 56°)
c=4.78-----> c=4.8
the answer Part 2)
the dimensions of the triangle N 2
are
a=12 A=56°
b=14 B=104.7°
c=4.8 C=19.3°
