Semd a pic of a graph bc I dont have paper
3. is the answer, as you can see D is one and a half units to the right of the y axis at a height of 3 units and C is one and a half units to the left of the y axis with the same height. So D is "reflected" about the y axis and only the x coordinate changes sign from positive to negative.
This is an interesting question. I chose to tackle it using the Law of Cosines.
AC² = AB² + BC² - 2·AB·BC·cos(B)
AM² = AB² + MB² - 2·AB·MB·cos(B)
Subtracting twice the second equation from the first, we have
AC² - 2·AM² = -AB² + BC² - 2·MB²
We know that MB = BC/2. When we substitute the given information, we have
8² - 2·3² = -4² + BC² - BC²/2
124 = BC² . . . . . . . . . . . . . . . . . . add 16, multiply by 2
2√31 = BC ≈ 11.1355