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3 years ago

Solve for Y

Mathematics

1 answer:

Lapatulllka [165]3 years ago

7 0

$\huge{\boxed{\sf{y= 12 - 6x}}}$

<u>Step by step explanation:</u>

Step 1:

$2x + \dfrac{y}{3} = 4$

Step 2:

$\implies \dfrac{2x \times 3 + y}{3} = 4$

Let take LCM

Step 3:

$\implies \dfrac{6x + y}{3} = 4$

Step 4:

$\implies6x + y = 4 \times 3$

Step 5:

$\implies6x + y = 12$

Step 6:

$\blue{\implies y= 12 - 6x✓}$

<h3>So option d is correct</h3>

thank you❤️

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There are 6 buses transporting students to a baseball game with 32 students on each bus. Each row at the baseball stadium seats

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6 buses with 32 students per bus.....6 x 32 = 192 students

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3 years ago

Factor f(x) = 15x^3 - 15x^2 - 90x completely and determine the exact value(s) of the zero(s) and enter them as a comma separated

Illusion [34]

Answer:

$x=-2,0,3$

Step-by-step explanation:

We have been given a function $f(x)=15x^3-15x^2-90x$ . We are asked to find the zeros of our given function.

To find the zeros of our given function, we will equate our given function by 0 as shown below:

$15x^3-15x^2-90x=0$

Now, we will factor our equation. We can see that all terms of our equation a common factor that is $15x$ .

Upon factoring out $15x$ , we will get:

$15x(x^2-x-6)=0$

Now, we will split the middle term of our equation into parts, whose sum is $-1$ and whose product is $-6$ . We know such two numbers are $-3\text{ and }2$ .

$15x(x^2-3x+2x-6)=0$

$15x((x^2-3x)+(2x-6))=0$

$15x(x(x-3)+2(x-3))=0$

$15x(x-3)(x+2)=0$

Now, we will use zero product property to find the zeros of our given function.

$15x=0\text{ (or) }(x-3)=0\text{ (or) }(x+2)=0$

$15x=0\text{ (or) }x-3=0\text{ (or) }x+2=0$

$\frac{15x}{15}=\frac{0}{15}\text{ (or) }x-3=0\text{ (or) }x+2=0$

$x=0\text{ (or) }x=3\text{ (or) }x=-2$

Therefore, the zeros of our given function are $x=-2,0,3$ .

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3 years ago

18-|-(-5)+(-4)|+7 Please

AlladinOne [14]

Answer:

Step-by-step explanation:

18-(+5-4)+7

18-1+7

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3 years ago

-0.312 as a fraction in simplest form

Black_prince [1.1K]

Answer:

It's -39/125

Step-by-step explanation:

Rewrite the decimal number as a fraction with 1 in the denominator

Multiply to remove 3 decimal places. Here, you multiply top and bottom by 103 = 1000

Find the Greatest Common Factor (GCF) of 312 and 1000, if it exists, and reduce the fraction by dividing both numerator and denominator by GCF = 8

Therefore

X=39/125

In conclusion,

−0.312=−39/125

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3 years ago

Read 2 more answers

Given: sinθ = -3/5, θ is a third quadrant angle, and tan φ = -7/24, φ is a second-quadrant angle; find cos(θ + φ])

Natali [406]

Answer:

First option: cos(θ + φ) = -117/125

Step-by-step explanation:

Recall that cos(θ + φ) = cos(θ)cos(φ) - sin(θ)sin(φ)

If sin(θ) = -3/5 in Quadrant III, then cos(θ) = -4/5.

Since tan(φ) = sin(φ)/cos(φ), then sin(φ) = -7/25 and cos(φ) = 24/25 in Quadrant II.

Therefore:

cos(θ + φ) = cos(θ)cos(φ) - sin(θ)sin(φ)

cos(θ + φ) = (-4/5)(24/25) - (-3/5)(-7/25)

cos(θ + φ) = (-96/125) - (21/125)

cos(θ + φ) = -96/125 - 21/125

cos(θ + φ) = -117/125

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2 years ago