Answer:
(a) The probability that a single randomly selected value lies between 158.6 and 159.2 is 0.004.
(b) The probability that a sample mean is between 158.6 and 159.2 is 0.0411.
Step-by-step explanation:
Let the random variable <em>X</em> follow a Normal distribution with parameters <em>μ</em> = 155.4 and <em>σ</em> = 49.5.
(a)
Compute the probability that a single randomly selected value lies between 158.6 and 159.2 as follows:
*Use a standard normal table.
Thus, the probability that a single randomly selected value lies between 158.6 and 159.2 is 0.004.
(b)
A sample of <em>n</em> = 246 is selected.
Compute the probability that a sample mean is between 158.6 and 159.2 as follows:
*Use a standard normal table.
Thus, the probability that a sample mean is between 158.6 and 159.2 is 0.0411.
Answer:
a)
b)
Step-by-step explanation:
Number of balls in the urn = 12
Number of white balls in the urn = 4
So, number of balls which are not white = 12 - 4 = 8
We know that probability = No. of outcomes/Total number of outcomes
Let denotes the event of getting white ball by A, B and C
a) each ball is replaced after being drawn.
Probability = Number of white balls/Total number of balls
Solution:
b)the balls that are withdrawn are not replaced.
Solution:
If A wins:
If A lost and B wins:
If A and B lost and C wins:
and so on....
what is b? from the first equation in the system, y + 2 = b.
<span><span>√<span><span><span>(<span><span>3<span>x4</span></span><span>y3</span></span>)</span>2</span>⋅<span>(<span><span>6x</span>y</span>)</span></span></span><span><span><span><span>3<span>x4</span></span><span>y3</span></span>2</span>⋅<span><span>6x</span>y</span></span></span>Pull terms out from under the radical.<span><span><span>3<span>x4</span></span><span>y3</span></span><span>√<span><span>6x</span><span>y</span></span></span></span>
Answer:
the answer is C - no association