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just olya [345]
3 years ago
13

If the area of a square is 49in2 what is one side length

Mathematics
1 answer:
adelina 88 [10]3 years ago
5 0

Answer:

one side length of the square is 7 in

Step-by-step explanation:

area of the square = 49 in^2

formula for

area of the square = length^2

49 = L^2

L = 7 in

can you give me brainlist plzz

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Which of the following statements is false regarding randomization?
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B

Step-by-step explanation:

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A local fish market is selling fish and lobsters by the pound. The fish, f, costs $4.25 a pound, while the lobster, l, costs $9.
malfutka [58]

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Answer:

  • 7 pounds of fish
  • 18.5 pounds of lobster

Step-by-step explanation:

Let x represent the number of pounds of lobster sold. Then 25.5-x is the number of pounds of fish. The total money made is ...

  4.25(25.5-x) +9.00x = 196.25

  4.75x + 108.375 = 196.25 . . . . . simplify

  4.75x = 87.875 . . . . . . . . . . . subtract 108.375

  x = 18.5 . . . . . . . . . . . . . . . divide by 4.75

The market sold 7 pounds of fish and 18.5 pounds of lobster.

8 0
3 years ago
Find the solution for x when X2 = 1.69
zhenek [66]

Answer:

x=1.3

Step-by-step explanation:

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3 0
3 years ago
Read 2 more answers
What is the solution of the system?<br> 2x + 5y = 14<br> 2 + 3y = 16<br><br> pls help
guajiro [1.7K]

Answer:

x=-14/3,y=14/3 but if there is x at the second wan.then,x=19/2,y=-1

4 0
3 years ago
A data set includes 103103 body temperatures of healthy adult humans having a mean of 98.998.9degrees°f and a standard deviation
dangina [55]

Answer:

98.9-2.62\frac{0.65}{\sqrt{103}}=98.73    

98.9+2.62\frac{0.65}{\sqrt{103}}=99.07    

So on this case the 99% confidence interval would be given by (98.73;99.07)    

Step-by-step explanation:

Previous concepts

A confidence interval is "a range of values that’s likely to include a population value with a certain degree of confidence. It is often expressed a % whereby a population means lies between an upper and lower interval".

The margin of error is the range of values below and above the sample statistic in a confidence interval.

Normal distribution, is a "probability distribution that is symmetric about the mean, showing that data near the mean are more frequent in occurrence than data far from the mean".

\bar X=98.9 represent the sample mean for the sample  

\mu population mean (variable of interest)

s=0.65 represent the sample standard deviation

n=103 represent the sample size  

Solution to the problem

The confidence interval for the mean is given by the following formula:

\bar X \pm t_{\alpha/2}\frac{s}{\sqrt{n}}   (1)

In order to calculate the critical value t_{\alpha/2} we need to find first the degrees of freedom, given by:

df=n-1=103-1=102

Since the Confidence is 0.99 or 99%, the value of \alpha=0.01 and \alpha/2 =0.005, and we can use excel, a calculator or a table to find the critical value. The excel command would be: "=-T.INV(0.005,102)".And we see that t_{\alpha/2}=2.62

Now we have everything in order to replace into formula (1):

98.9-2.62\frac{0.65}{\sqrt{103}}=98.73    

98.9+2.62\frac{0.65}{\sqrt{103}}=99.07    

So on this case the 99% confidence interval would be given by (98.73;99.07)    

6 0
3 years ago
Read 2 more answers
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