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UkoKoshka [18]
4 years ago
11

Starting with the pumpkin as your projectile, gather data and answer the following questions. a. With an initial speed of 18m/s

and no air resistance, what angle must the cannon be at to hit the bull’s eye?75degreesb. Clear your results from part a. Now add air resistanceand answer the same question.70 degreesc. Clear your results from part b and remove the air resistance. Collect data to figure out how the angle must be changed to hit the bull’s eye as the initial speed increasesCol1 Initial speed 14m/s 18m/s 22m/s 26m/sCol2 Angle 65 75 80 83
Physics
1 answer:
erma4kov [3.2K]4 years ago
8 0

Answer:

a) 75°

b) 72° (with drag coefficient = 2 and altitude = 1 m)

c) 63° (with initial speed = 14 m/s)

80° (initial speed = 22 m/s)

83° (initial speed = 26 m/s)

Explanation:

By using projectile motion simulator from the website, "http://phet.colorado.edu/sims/projectile-motion/projectile-motion.swf", desired answers can be found accordingly.

a) When we need to arrange degree at 75° , it hits the bull's eye.

b) By adding air resistence with drag coefficient = 2 and altitude = 1 m,

to hit the bull's eye, we need to arrange degree at 72°

c) With initial speed = 14 m/s, we need to arrange degree at 63°

With initial speed = 22 m/s, we need to arrange degree at 80°

With initial speed = 26 m/s, we need to arrange degree at 83°

So, as the initial speed increases, the angle also increases.

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A car has a mass of 1600 kg. It is stuck in the snow and is being pulled out by a cable that applies a force of 7560 N due north
sergiy2304 [10]

Answer:

Acceleration of the car will be a=0.1375m/sec^2

Explanation:

We have given mass of the ball m = 1600 kg

Force in north direction F= 7560 N

Resistance force which opposes the movement of car F_R=7340N

So net force on the car F_{net}=F-F_R=7560-7340=220N

According to second law of motion we know that F=ma

So 220=1600\times a

a=0.1375m/sec^2

7 0
3 years ago
The driver of a stationary car hears a siren of an approaching police car at a frequency of 280Hz. If the actual frequency of th
deff fn [24]

Answer:

The speed of the police car is 294 m/s

Explanation:

Given;

frequency of the siren in air, f = 280 Hz

speed of sound in air, v = 343 m/s

Determine the wavelength of the sound in air to the stationary car:

v = fλ

where;

λ is wavelength of the sound

λ = v/f

λ = 343 / 280

λ = 1.225 m

Now, determine the speed at which the police car is approaching the stationary car;

The actual frequency of the police car, F = 240 Hz

V = Fλ

Where;

V is speed of the police car

λ is the distance between the police car and the stationary car, (wavelength)

V = 240 x 1.225

V = 294 m/s

Therefore, the speed of the police car is 294 m/s

5 0
3 years ago
A hydraulic press has a safety feature which consists of a hydraulic cylinder with a piston at one end and a safety valve at the
Sergio039 [100]

Answer:

Explanation:

radius of cylinder r₁ = .02 m

radius of safety valve r₂ = .0075 m

force exerted by spring on safety valve = 950 x .0085 = 8.075 N .

Force required on piston of cylinder = F

Applying Pascal's law

8.075 / 3.14 x .0075²  =  F / 3.14 x .02²

F = 8.075 x .02² / .0075²

= 8.075 x 7.111

= 57.42 N .

6 0
3 years ago
A football player runs from his own goal line to the opposing team's goal line, returning to his forty-yard line, all in 22.4 s.
Bumek [7]
I assume L=120 yards as the length of the football field.

1) The average speed is given by the total distance covered by the player divided by the time taken.
The total distance covered to go from one goal line to the other and then back to the 40-yards line is
S=120y+(120-40)y=120y+80y=200 y
And the time taken is t=22.4 s, so the average speed of the player is
v= \frac{S}{t}= \frac{200 y}{22.4 s}=8.93 y/s

2) The find the average velocity, we should also consider the direction (and the sign) of the velocity.
In the the first part of the motion, the player goes from one goal line to the other one, so he covers 120 y. However, in the second part of the motion he goes back by 80 y. Therefore, the net displacement of the player is
S=120 y-80 y=40 y
and so, the average velocity is
v= \frac{S}{t}= \frac{40 y}{22.4 s}= 1.79 y/s
6 0
3 years ago
A ball is thrown straight up into the air. At each of the following instants, is the ball's acceleration ay equal to g, −g, 0, g
Leto [7]

Answer:

a= (-g) from the moment the ball is thrown, until it stops in the air.

a = (0) when the ball stops in the air.

a = (g) since the ball starts to fall.

Explanation:

The acceleration is <em>(-g)</em> <em>from the moment the ball is thrown, until it stops in the air</em> because the movement goes in the opposite direction to the force of gravity. In the instant <em>when the ball stops in the air the acceleration is </em><em>(0)</em> because it temporarily stops moving. Then, <em>since the ball starts to fall, the acceleration is </em><em>(g)</em><em> </em>because the movement goes in the same direction of the force of gravity

6 0
3 years ago
Read 2 more answers
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