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Amanda [17]
3 years ago
12

A boat uses its motor to increase its speed from 5 m/s to 7 m/s. If the boat has a mass of

Physics
1 answer:
Margarita [4]3 years ago
5 0

Answer:

J = 500 kg-m/s

Explanation:

Given that,

Initial speed of the motor, u = 5 m/s

Final speed of the motor, v = 7 m/s

Mass of the boat, m = 250 kg

We need to find the impulse applied by the motor. We know that impulse is equal to the change in momentum. It is represented by letter J.

J = m(v-u)

J = 250 (7-5)

J = 500 kg-m/s

Hence, the impulse applied by the motor is 500 kg-m/s.

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Answer:

The maximum height that a cannonball fired at 420 m/s at a 53.0° angles is 5740.48m.

hmax = 5740.48 m

Explanation:

This is an example of parabolic launch. A cannonball is fired on flat ground at 420 m/s at a 53.0° angle and we have to calculate the maximum height that it reach.

V₀ = 420m/s and θ₀ = 53.0°

So, when the cannonball is fired it has horizontal and vertical components:

V₀ₓ = V₀ cos θ₀ = (420m/s)(cos 53°) = 252.76 m/s

V₀y = V₀ cos θ₀ = (420m/s)(cos 53°) = 335.43m/s

When the cannoball reach the maximum height the vertical velocity component is zero, that happens in a tₐ time:

Vy = V₀y - g tₐ = 0

tₐ = V₀y/g

tₐ = (335.43m/s)/(9.8m/s²) = 34.23s

Then, the maximum height is reached in the instant tₐ = 34.23s:

h = V₀y tₐ - 1/2g tₐ²

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hmax = 5740.48m

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