Answer:OB=58.3m
Explanation:
So here cow wanders 30m in north and turns 22 degrees in right side and moves 40m more, as shown in figure given.
now take the starting point as a origin such that cow moves in x-y co-ordinate axis.
As shown in figure length OA is the length when cow moves in north or y direction. Later she takes 22 degrees turn to right and moves 40m more.
So the final displacement is the length of cow from the origin that is length OB.
now co-ordinates of B are [40cos22°,40sin22°+30] i.e [37.084,44.984]
now displacement of cow= length of OB
= ![\sqrt{[37.084]^{2}+[44.984]^{2} }](https://tex.z-dn.net/?f=%5Csqrt%7B%5B37.084%5D%5E%7B2%7D%2B%5B44.984%5D%5E%7B2%7D%20%20%7D)
=![\sqrt{3398.78}](https://tex.z-dn.net/?f=%5Csqrt%7B3398.78%7D)
OB =![58.3](https://tex.z-dn.net/?f=58.3)
32,100 Millimeters
3,210 Centimeters
3.21 Decameters
Hope It Helps
Answer:
wavelength = 24 m
Period = 10 s
f = 0.1 Hz
Amplitude = 4 m
Explanation:
Wavelength:
Since the boats are at crest and trough, respectively at the same time. Hence, the horizontal distance between them is the wavelength of the wave:
<u>wavelength = 24 m</u>
Period:
The period is given as:
![Period = \frac{time}{no.\ of\ cycles} \\\\Period = \frac{10\ s}{1}\\\\](https://tex.z-dn.net/?f=Period%20%3D%20%5Cfrac%7Btime%7D%7Bno.%5C%20of%5C%20cycles%7D%20%5C%5C%5C%5CPeriod%20%3D%20%5Cfrac%7B10%5C%20s%7D%7B1%7D%5C%5C%5C%5C)
<u>Period = 10 s</u>
<u></u>
Frequency:
The frequency is given as:
![f = \frac{1}{time\ period}\\\\f = \frac{1}{10\ s}\\\\](https://tex.z-dn.net/?f=f%20%3D%20%5Cfrac%7B1%7D%7Btime%5C%20period%7D%5C%5C%5C%5Cf%20%3D%20%5Cfrac%7B1%7D%7B10%5C%20s%7D%5C%5C%5C%5C)
<u>f = 0.1 Hz</u>
<u></u>
Amplitude:
Amplitude will be half the distance between extreme points, that is, crest and trough:
Amplitude = 8 m/2
<u>Amplitude = 4 m</u>
ANSWER: THE ANSWER IS SUMMER
I think it would be wires!