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Hitman42 [59]
3 years ago
10

Simplify the expression z2-z(z+3)+3z

Mathematics
1 answer:
Maslowich3 years ago
8 0
<span>z2-z(z+3)+3z
=> z2 - z2 - 3z + 3z 
=> 0 
we can cancel the like terms if they have different signs ..

Hope it helps !!</span>
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(15-6)-3 = 15 - (6 -3) dose this make sense or nonsense?
solmaris [256]
No it does not make sense. You misused the parenthesis and the "-" multiplied the variables within the parenthesis and as a result one of them subtracted (15 - 6) by 3 and the other added, which is why the final values are 6 apart. This is not how you use properties in math.
(15 - 6) - 3 = 9 - 3 = 6
15 - (6 - 3) = 15 - 3 = 12
7 0
4 years ago
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The table shows a basketball player score in 5 Games how many points must the basketball players score in the next game to achie
bogdanovich [222]

Answer:

You would have to score 17 points.

Step-by-step explanation:

13x6=78 is the points you have to reach to get 13 points per game.

Add up all numbers, which is 61.

78-61=17

That is your answer.

3 0
4 years ago
Find the area of the parallelogram
MissTica

Answer:

A = b x h

Step-by-step explanation:

Area = base x height

6 0
4 years ago
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WILL MARKBRANLIEST<br> ...
MA_775_DIABLO [31]
Make ratios.

12/16: 15/x

cross multiply

12(x) = 12x
16(15) = 240

12x = 240

isolate the x, divide 12 from both sides

12x/12 = 240/12

x = 20

D) 20 km is your answer

hope this helps
5 0
3 years ago
What is the average rate of change of the function over the interval x = 0 to x = 8?
notsponge [240]
To find the average rate of change, use the following formula:

\frac{f(b) - f(a)}{b-a}

a and b represent the values of the interval:

a = 0, b = 8

Simplify the original equation by combining like terms:

2x - 13x = -11x
f(x) = -11x + 5

Plug the interval values into the f(x) equation:

f(0) = -11(0) + 5 = 0 + 5 = 5
f(8) = -11(8) + 5 = -88 + 5 = -83

Plug in these values into the average rate of change formula:

\frac{-83 - 5}{8 - 0} =  \frac{-88}{8} = -11

The average rate of change over this interval is -11.
4 0
3 years ago
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