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Debora [2.8K]
3 years ago
13

What's the difference between artificial and natural radioisotopes?​

Physics
1 answer:
Soloha48 [4]3 years ago
6 0
The spontaneous emission of radiations from an unstable nuclei is known as natural radioactivity. on the other hand, The process of emission of radiations from naturally occurring isotopes when they are bombarded with sub-atomic particles or high levels of X-rays or gamma rays called artificial radioactivity.
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The _____ usually occur in nature as combined elements.
notsponge [240]
The transition metals usually occur in as combine state. .
6 0
3 years ago
Carrier concentration for n type​
pav-90 [236]

Answer:

Consider an n-type silicon semiconductor at T = 300°K in which Nd = 1016 cm-3 and Na = 0. The intrinsic carrier concentration is assumed to be ni = 1.5 x 1010 cm-3. - Comment Nd >> ni, so that the thermal-equilibrium majority carrier electron concentration is essentially equal to the donor impurity concentration.

Explanation:

7 0
3 years ago
In a head-on collision, a ball of mass 0.3 kg travelling with velocity 2.8 m/s in the positive x-direction hits a stationary sec
Pie

Answer:

The final velocity of the first ball (0.3 kg) is 0.4 m/s in negative x direction.

Explanation:

Given;

mass of the first object, m₁ = 0.3 kg

initial velocity of the first ball, u₁ = 2.8 m/s

mass of the second ball, m₂ = 0.4 kg

initial velocity of the second ball, u₂ = 0

let the final velocity of the first ball, = v₁

let the final velocity of the second ball, = v₂

Apply the principle of conservation of linear momentum;

m₁u₁ + m₂u₂ = m₁v₁ + m₂v₂

(0.3 x 2.8) + (0.4 x 0) = 0.3v₁ + 0.4v₂

0.84 = 0.3v₁ + 0.4v₂

2.8 = v₁ + 1.333v₂ -------equation (1)

Apply one-direction velocity;

u₁ + v₁ = u₂ + v₂

2.8 + v₁ = 0 + v₂

v₂ = 2.8 + v₁

substitute the value of v₂ into equation (1)

2.8 = v₁ + 1.333v₂

2.8 = v₁ + 1.333(2.8 + v₁)

2.8 = v₁ + 3.732 + 1.333v₁

2.8 - 3.732 = v₁ + 1.333v₁

-0.932 = 2.333v₁

v₁ = -0.932 / 2.333

v₁ = -0.4 m/s

Therefore, the final velocity of the first ball (0.3 kg) is 0.4 m/s in negative x direction.

8 0
3 years ago
Falling objects drop with an average acceleration of 9.8 m/sec/sec, or 9.8 m /s2. If an object falls from the top of a tall buil
Lena [83]

Use the velocity expression for uniform acceleration and solve for t: v = v0 + at. v0 is zero since the object is at rest. 49 m/s = a(t), and solve for t. t = 49 m/s / 9.8 = 5 seconds.

5 0
3 years ago
A woman does 236 J of work
Ratling [72]

Answer:

The woman's force was directed 59.22⁰ to the horizontal.

Explanation:

Given;

work done by the woman, W = 236 J

distance through the load was moved, d = 24.4 m

applied force, F = 18.9 N

inclination of the force, = θ

The work done by the woman is calculated as;

W = Fdcosθ

cos \ \theta = \frac{W}{Fd} \\\\cos \ \theta = \frac{236 }{18.9 \times 24.4} \\\\cos \ \theta =  0.5118\\\\\theta = cos^{-1} ( 0.5118)\\\\\theta =59.22^0

Therefore, the woman's force was directed 59.22⁰ to the horizontal.

8 0
3 years ago
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