Me - HS_SCLPhysical Science,

A type of cuckoo clock keeps time by having a mass bouncing on a spring, usually something cute like a cherub in a chair. What f

babymother [125]

Answer:

the force constant k = 2.369 N/m

Explanation:

Given that:

A type of cuckoo clock keeps time by having a mass bouncing on a spring, usually something cute like a cherub in a chair.

with period T = 0.500 s and a mass of 0.0150 kg, Then the force constant can be calculated by using the formula:

$\mathtt{T = 2 \pi \ \sqrt{\dfrac{m}{k} }}$

where;

T = time period

m = mass

k = force constant.

By making k the subject of the formula; we have:

$\mathtt{T^2 = 4 \pi^2 (\dfrac{m}{k})}$

$\mathtt{k =\dfrac{4 \pi ^2 \ m}{T^2}}$

replacing our given values , we have:

$\mathtt{k =\dfrac{4 (3.142) ^2 \ \times 0.0150 }{0.5^2}}$

$\mathtt{k =\dfrac{39.49 \ \times 0.0150 }{0.25}}$

$\mathtt{k =\dfrac{0.59235 }{0.25}}$

k = 2.369 N/m

7 0

3 years ago

Kim designed an experiment to show how heat can be transferred from one place to another. The steps of the experiment are shown

Radda [10]

Heat transfer by conduction, since kim is trying to show that heat travels from one end of the rod to the other. This is nothing but conduction

3 0

3 years ago

If the same force is applied to an object with a large mass it will have a blank acceleration

kati45 [8]

Answer:

If the same force is applied to an object with a large mass it will have a <u>smaller (lesser) </u>acceleration

Explanation:

force and mass are inversely proportional. force and acceleration are directly proportional. which means greater mass have smaller acceleration and smaller mass has greater acceleration. this is due to newtons second law of motion.

3 0

3 years ago

Read 2 more answers

MODERN PHYSICS

frosja888 [35]

Answer:

D. n=6 to n=2

Explanation:

Given;

energy of emitted photon, E = 3.02 electron volts

The energy levels of a Hydrogen atom is given as; E = -E₀ /n²

where;

E₀ is the energy level of an electron in ground state = -13.6 eV

n is the energy level

From the equation above make n, the subject of the formula;

n² = -E₀ / E

n² = 13.6 eV / 3.02 eV

n² = 4.5

n = √4.5

n = 2

When electron moves from higher energy level to a lower energy level it emits photons;

$E = E_0(\frac{1}{n_1^2}-\frac{1}{n_2^2} )\\\\\frac{1}{n_1^2}-\frac{1}{n_2^2} = \frac{E}{E_o} \\\\\frac{1}{4} -\frac{1}{n_2^2} = \frac{3.02}{13.6} \\\\\frac{1}{4} -\frac{1}{n_2^2} =0.222\\\\\frac{1}{n_2^2} = 0.25 - 0.22\\\\\frac{1}{n_2^2} = 0.03\\\\n_2^2 = 33.33\\\\n_2 = \sqrt{33.33} = 6$

For a photon to be emitted, electron must move from higher energy level to a lower energy level. The higher energy level is 6 while the lower energy level is 2

Therefore, The electron energy-level transition is from n = 6 to n = 2

3 0

3 years ago

A disk has 128 tracks of 32 sectors each, on each surface of eight platters. The disk spins at 3600 RPM and takes 15 ms to move

Serga [27]

Answer:

the longest time needed to read an arbitrary sector located anywhere on the disk is 2971.24 ms

Explanation:

Given the data in the question;

first we determine the rotational latency

Rotational latency = 60/(3600×2) = 0.008333 s = 8.33 ms

To get the longest time, lets assume the sector will be found at the last track.

hence we will access all the track, meaning that 127 transitions will be done;

so the track changing time = 127 × 15 = 1905 ms

also, we will look for the sectors, for every track rotations that will be done;

128 × 8.33 = 1066.24 ms

∴The Total Time = 1066.24 ms + 1905 ms

Total Time = 2971.24 ms

Therefore, the longest time needed to read an arbitrary sector located anywhere on the disk is 2971.24 ms

7 0

3 years ago