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Lubov Fominskaja [6]
3 years ago
11

The equilibrium-constant expression depends on the ________ of the reaction. Group of answer choices temperature stoichiometry m

echanism the quantities of reactants and products initially present stoichiometry and mechanism
Chemistry
1 answer:
slavikrds [6]3 years ago
7 0

Answer:

temperature and mechanism

Explanation:

Arrhenius equation gives us the idea about the factors affecting equilibrium constant.It is given as:

<h3>k=Ae^{\frac{-E_{a} }{RT} }</h3>

where k=equilibrium constant

          A=pre-exponential factor

          E_{a}=Activation energy

          T=temperature

          R=Universal gas constant

<h3>It is clear that k depends only on temperature and activation energy.</h3>

Activation energy of a reaction is different for different mechanisms or pathways.Hence k depends on both temperature and mechanism.

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In ____________, particles change directly from a solid to a gas
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Answer:

Sublimation.

Explanation:

Sublimation is the conversion between the solid and the gaseous phases of matter, with no intermediate liquid stage

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What is plate tectonics
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Answer:

Plate tectonics is a scientific theory describing the large-scale motion of seven large plates and the movements of a larger number of smaller plates of Earth's lithosphere, since tectonic processes began on Earth between 3.3 and 3.5 billion years ago.

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The formal charge is the "charge" an element would have in a molecule or ion if all of the bonding electrons were shared equally
Fiesta28 [93]

Answer:

Explanation:

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5 0
3 years ago
Use de Broglie's hypothesis to determine the speed of the electron in a hydrogen atom when in the n = 5 orbit, whose radius is 1
andriy [413]

Answer:

Velocity = 4.41×10⁵ m/s

Explanation:

The force of attraction between the nucleus and the electron is equal to the centrifugal force acting on the  outermost electron due to circular rotation. It can be mathematically written as:

\frac {K\times q^2}{r^2}=\frac {m\times v^2}{r}

Where,

K is the Coulomb's constant having value 9×10⁹ N. m²/C²

q is the charge on the electron or the proton which is 1.6×10⁻¹⁹ C

r is the radius of the atom

m is the mass of the electron having value 9.1×10⁻³¹ Kg

v is the velocity of the electron.

The equation can be written to calculate the velocity as:

v=\sqrt {\frac {K\times q^2}{m\times r}}

Given that:

r = 1.3×10⁻⁹ m

So,

v=\sqrt {\frac {9\times 10^9\times (1.6\times 10^{-19})^2}{9.1\times 10^{-31}\times 1.3\times 10^{-9}}}

<u>Velocity = 4.41×10⁵ m/s</u>

4 0
3 years ago
A 0.9440 g sample of a mixture of NaCl and KCl is dissolved in water, and the solution is then treated with an excess of AgNO3 t
Gnom [1K]

Answer : The percent by mass of NaCl and KCl are, 18.11 % and 81.88 % respectively.

Explanation :

As we know that when a mixture of NaCl and KCl react with excess AgNO_3 then the silver ion react with the chloride ion in both NaCl and KCl to form silver chloride.

Let the mass of NaCl be, 'x' grams and the mass of KCl will be, (0.9440 - x) grams.

The molar mass of NaCl and KCl are, 58.5 and 74.5 g/mole respectively.

First we have to calculate the moles of NaCl and KCl.

\text{Moles of }NaCl=\frac{\text{Mass of }NaCl}{\text{Molar mass of }NaCl}=\frac{xg}{58.5g/mole}=\frac{x}{58.5}moles

\text{Moles of }KCl=\frac{\text{Mass of }KCl}{\text{Molar mass of }KCl}=\frac{(0.9440-x)g}{74.5g/mole}=\frac{(0.9440-x)}{74.5}moles

As, each mole of NaCl and KCl gives one mole of chloride ions.

So, moles of chloride ions in NaCl = \frac{x}{58.5}moles

Moles of chloride ions in KCl = \frac{(0.9440-x)}{74.5}moles

The total moles of chloride ions = \frac{x}{58.5}moles+\frac{(0.9440-x)}{74.5}moles

Now we have to calculate the moles of AgCl.

As we know that, this amount of chloride ion is same as the amount chloride ion present in the AgCl precipitate. That means,

Moles of AgCl = Moles of chloride ion = \frac{x}{58.5}moles+\frac{(0.9440-x)}{74.5}moles

Now we have to calculate the moles of AgCl.

The molar mass of AgCl = 143.32 g/mole

\text{Moles of }AgCl=\frac{\text{Mass of }AgCl}{\text{Molar mass of }AgCl}=\frac{1.903g}{143.32g/mole}=0.0133moles

Now we have to determine the value of 'x'.

Moles of AgCl = \frac{x}{58.5}moles+\frac{(0.9440-x)}{74.5}moles

0.0133 mole = \frac{x}{58.5}moles+\frac{(0.9440-x)}{74.5}moles

By solving the term, we get the value of 'x'.

x=0.171g

The mass of NaCl = x = 0.171 g

The mass of KCl = (0.9440 - x) = 0.9440 - 0.171 = 0.773 g

Now we have to calculate the mass percent of NaCl and KCl.

\text{Mass percent of }NaCl=\frac{\text{Mass of }NaCl}{\text{Total mass of mixture}}\times 100=\frac{0.171g}{0.9440g}\times 100=18.11\%

\text{Mass percent of }KCl=\frac{\text{Mass of }KCl}{\text{Total mass of mixture}}\times 100=\frac{0.773g}{0.9440g}\times 100=81.88\%

Therefore, the percent by mass of NaCl and KCl are, 18.11 % and 81.88 % respectively.

7 0
4 years ago
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