A gas has a volume of 350 mL at 45 oK. If the volume changes to 400 mL, what is the new temperature?

Chemistry

1 answer:

elena-14-01-66 [18.8K]2 years ago

4 0

Answer:

T₂ = 39.4 °K

Explanation:

Because you are only dealing with volume and temperature, you can use Charles' Law to find the missing value. The formula looks like this:

V₁ / T₁ = V₂ / T₂

In this formula, "V₁" and T₁" represent the initial volume and temperature. "V₂" and "T₂" represent the final volume and temperature. You have been given values for all of the variables except for "T₂". Therefore, by plugging these values into the formula, you can simplify to find the answer.

V₁ = 350 mL T₁ = 45 °K

V₂ = 400 mL T₂ = ?

V₁ / T₁ = V₂ / T₂ <----- Charles' Law formula

(350 mL)(45 °K) = (400 mL)T₂ <----- Insert values into variables

15750 = (400 mL)T₂ <----- Multiply left side

39.4 = T₂ <----- Divide both sides by 400

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