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murzikaleks [220]
2 years ago
14

Which term describes this reaction? upper c upper h subscript 3 upper b r (a q) plus upper o upper h superscript minus (a q) rig

ht arrow upper c upper h subscript 3 upper o upper h (a q) plus upper b r superscript minus (a q). addition condensation elimination substitution
Chemistry
1 answer:
Veronika [31]2 years ago
6 0

The reaction is a substitution reaction since bromide ion was replaced by hydroxide ion.

<h3>What is a chemical reaction?</h3>

A chemical reaction is a change which results in a the permanent rearrangements of the atoms and constituents of a substance such that new substances are formed.

The given reaction is a as follows:

CH_3Br (aq) + OH^{-} (aq) \rightarrow CH_3OH (aq) + Br^{-} (aq) \\

Bromide ion was replaced by hydroxide ion.

Therefore, the reaction is a substitution reaction.

Learn more about chemical reactions at: brainly.com/question/16416932

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Ammonia has been studied as an alternative "clean" fuel for internal combustion engines, since its reaction with oxygen produces
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The question is incomplete, here is the complete question:

Ammonia has been studied as an alternative "clean" fuel for internal combustion engines, since its reaction with oxygen produces only nitrogen and water vapor, and in the liquid form it is easily transported. An industrial chemist studying this reaction fills a 5.0 L flask with 2.2 atm of ammonia gas and 2.4 atm of oxygen gas at 44.0°C. He then raises the temperature, and when the mixture has come to equilibrium measures the partial pressure of nitrogen gas to be 0.99 atm.

Calculate the pressure equilibrium constant for the combustion of ammonia at the final temperature of the mixture. Round your answer to 2 significant digits.

<u>Answer:</u> The pressure equilibrium constant for the reaction is 32908.46

<u>Explanation:</u>

We are given

Initial partial pressure of ammonia = 2.2 atm

Initial partial pressure of oxygen gas = 2.4 atm

Equilibrium partial pressure of nitrogen gas = 0.99 atm

The chemical equation for the reaction of ammonia and oxygen gas follows:

                    4NH_3(g)+3O_2(g)\rightarrow 2N_2(g)+6H_2O(g)

<u>Initial:</u>               2.2          2.4

<u>At eqllm:</u>        2.2-4x      2.4-3x         2x        6x

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\Rightarrow 2x=0.99\\\\x=0.495

So, equilibrium partial pressure of ammonia = (2.2 - 4x) = [2.2 - 4(0.495)] = 0.22 atm

Equilibrium partial pressure of oxygen gas = (2.4 - 3x) = [2.4 - 3(0.495)] = 0.915 atm

Equilibrium partial pressure of water vapor = 6x = (6 × 0.495) = 1.98 atm

The expression of K_p for above equation follows:

K_p=\frac{(p_{N_2})^2\times (p_{H_2O})^6}{(p_{NH_3})^4\times (p_{O_2})^3}  

Putting values in above equation, we get:

K_p=\frac{(0.99)^2\times (1.98)^6}{(0.22)^4\times (0.915)^3}\\\\K_p=32908.46

Hence, the pressure equilibrium constant for the reaction is 32908.46

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