Which term describes this reaction? upper c upper h subscript 3 upper b r (a q) plus upper o upper h superscript minus (a q) rig
1 answer:
The reaction is a substitution reaction since bromide ion was replaced by hydroxide ion.
<h3>What is a chemical reaction?</h3>A chemical reaction is a change which results in a the permanent rearrangements of the atoms and constituents of a substance such that new substances are formed.
The given reaction is a as follows:
Bromide ion was replaced by hydroxide ion.
Therefore, the reaction is a substitution reaction.
Learn more about chemical reactions at: brainly.com/question/16416932
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Answer:
the final volume of the gas is = 1311.5 mL
Explanation:
Given that:
a sample gas has an initial volume of 61.5 mL
The workdone = 130.1 J
Pressure = 783 torr
The objective is to determine the final volume of the gas.
Since the process does 130.1 J of work on its surroundings at a constant pressure of 783 Torr. Then, the pressure is external.
Converting the external pressure to atm ; we have
External Pressure :
The workdone W = V
The change in volume ΔV=
ΔV =
ΔV =
ΔV = 1.25 L
ΔV = 1250 mL
Recall that the initial volume = 61.5 mL
The change in volume V is
multiply through by (-), we have:
= 1250 mL + 61.5 mL
= 1311.5 mL
∴ the final volume of the gas is = 1311.5 mL
The coefficients of the hydrocarbon and water is 61 and it is explained below.
Explanation:
We have to balance the chemical equation that describes the combustion of octane C₈H₁₈. The combustion of octane involves burning this hydrocarbon in the presence of excess oxygen,O 2. Because octane is a hydrocarbon, that is the compound that contains only carbon and hydrogen, the reaction will produce two products carbon dioxide CO 2 and water H 2 O.
The unbalanced chemical equation is
C₈H₁₈ + O₂ → CO₂ + H₂O
To balance this equation, we have 8 present on the reactant side, so multiply the carbon dioxide by 8 to get 8 atoms of carbon on the products side.
C₈H₁₈ + O₂ → 8 CO₂ + H₂O
Now, we have 18 on the reactant side and 2 on the products side, so multiply the water molecule by 9 to get
C₈H₁₈ + O₂ → 8 CO₂ + 9 H₂O
8 * 2 atoms O + 9 *1 atoms O = 25 atoms O
By adding fractional coefficient to O₂ we get
C₈H₁₈ + O₂ → 8 CO₂ + 9 H₂O
Multiply all the coefficients by 2 we get,
2C₈H₁₈ + ( * 2) O₂ → 8 * 2 CO₂ + 9* 2 H₂O
The balance equation is
2C₈H₁₈ + 25 O₂ → 16 CO₂ + 18 H₂O
Add the coefficients to get their sum
= 2 +25 + 16 +18 = 61
Thus, The coefficients of the hydrocarbon and water is 61