Solve for x over the real numbers:2 x^2 - 3 x - 2 = x + 4
Subtract x + 4 from both sides:2 x^2 - 4 x - 6 = 0
The left hand side factors into a product with three terms:2 (x - 3) (x + 1) = 0
Divide both sides by 2:(x - 3) (x + 1) = 0
Split into two equations:x - 3 = 0 or x + 1 = 0
Add 3 to both sides:x = 3 or x + 1 = 0
Subtract 1 from both sides:Answer: x = 3 or x = -1
Ok here is what I think.
Let us first number these statements, as #1, and #2.
First statement: 3x + 8y = 12 (1)
Second Statement: 2x + 2y = 3 (2)
Now, we can work from this.
We want to make one of the equations be equal to 0 so that at the end when we check they can be equal to each other.
Let us use 4.
3x+8y=12 1-8x-8y=-12 2
This gives us:-5x = 0
Now we should try and isolate x so we can substitute it into one of the equations.
We have -5x=0
and x=0
3(0)+8y=12
8y=12
y=12/8
y=3/2
Plug in these new equations
y=3/2 and y=0 into any of the first equations
3x+8y=12 3(0)+8(3/2)= 12 8(3/2)=12 4(3)=12 12=12
Now we know it works, thats our check^^
Answer:151500
Step-by-step explanation:the is the answer
Answer:
Okie when you do these you got to give all information
Step-by-step explanation: because people can help you instead of looking at a picture wonderin what they are they are supposed to do
