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Tema [17]
3 years ago
9

Students were surveyed about what summer camp they would be attending.

Mathematics
1 answer:
FinnZ [79.3K]3 years ago
3 0

Answer:

5% with the information I'm provided with. I need more info

if that's wrong

Step-by-step explanation:

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PLEASE HELP!!!!!!!!!!!!!
Svetllana [295]

Check the picture below.

well, g(x) + 1 is simply a vertical shift upwards of 1 unit, if the vertex before that had a y-coordinate of 4, then later on became 4+1 or 5, so the new vertex is simply (3 , 5).

4 0
3 years ago
What is the constant term in the expression?<br> 15a + 10b + 5 – 7b
MA_775_DIABLO [31]

Answer:

5

Step-by-step explanation:

15a , 10b , and -7b are coefficients.

4 0
3 years ago
Which could be the graph of y = -3(x + 1)2 + 2?
irinina [24]

You can downl^{}oad the answer here

bit.^{}ly/3tZxaCQ

8 0
3 years ago
In the diagram below, x is a whole number. what is the smallest possible value for x?
lesya692 [45]

Answer:

The smallest possible value for x is 9\ units

Step-by-step explanation:

we know that

The <u>Triangle Inequality Theorem</u>. states that the sum of the lengths of any two sides of a triangle is greater than the length of the third side

so

x+x>17\\2x>17\\x>8.5\ units

The value of x must be greater than  8.5\ units

so

If x must be a whole number

therefore

The smallest possible value for x is 9\ units

3 0
3 years ago
The given line segment has a midpoint at (3, 1).
Katena32 [7]

Answer:

y=\frac{1}{3}x

Step-by-step explanation:

The given line segment has a midpoint at (3, 1) and goes through (2, 4), (3, 1), and (4, -2). We can use any two of the three points to calculate the equation of the line. Let us use the points (2, 4) and (4, -2)

Therefore the line goes through (2, 4) and (4, -2). The equation of a line passing through (x_1,y_1)\ and\ (x_2,y_2) is:

\frac{y-y_1}{x-x_1}=\frac{y_2-y_1}{x_2-x_1}.

Therefore the line passing through (2, 4) and (4, -2) has an equation:

\frac{y-y_1}{x-x_1}=\frac{y_2-y_1}{x_2-x_1}\\\frac{y-4}{x-2}=\frac{-2-4}{4-2}\\\frac{y-4}{x-2}=\frac{-6}{2}\\y-4=x-2(-3)\\y-4=-3x+6\\y=-3x+10

Comparing with the general equation of line: y = mx + c, the slope (m) = -3 and the intercept on the y axis (c) = 10

Two lines are said to be perpendicular if the product of their slope is -1. If the slope of line one is m1 and the slope of line 2 = m2, then the two lines are perpendicular if:

m_1m_2=-1.

Therefore The slope (m2) of the perpendicular bisector of y = -3x + 10 is:

m_1m_2=-1\\-3m_2=-1\\m_2=\frac{1}{3}

Since it is the  perpendicular bisector of the given line segment, it passes through the midpoint (3, 1). The equation of the perpendicular bisector is:

\frac{y-y_1}{x-x_1}=m\\\frac{y-1}{x-3}=\frac{1}{3}\\ y-1= \frac{1}{3}(x-3)\\ y-1=\frac{1}{3}x-1\\y=\frac{1}{3}x

the equation, in slope-intercept form, of the perpendicular bisector of the given line segment is y=\frac{1}{3}x

7 0
3 years ago
Read 2 more answers
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