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natima [27]
3 years ago
12

A market surveyor wishes to know how many energy drinks teenagers drink each week. They want to construct a 98% confidence inter

val with an error of no more than 0.08. A consultant has informed them that a previous study found the mean to be 5.9 energy drinks per week and found the variance to be 1.21. What is the minimum sample size required to create the specified confidence interval
Mathematics
1 answer:
frosja888 [35]3 years ago
3 0

Answer:

The minimum sample size required to create the specified confidence interval is 1024.

Step-by-step explanation:

We have that to find our \alpha level, that is the subtraction of 1 by the confidence interval divided by 2. So:

\alpha = \frac{1-0.98}{2} = 0.01

Now, we have to find z in the Ztable as such z has a pvalue of 1-\alpha.

So it is z with a pvalue of 1-0.01 = 0.99, so z = 2.327

Now, find the margin of error M as such

M = z*\frac{\sigma}{\sqrt{n}}

In which \sigma is the standard deviation of the population and n is the size of the sample.

What is the minimum sample size required to create the specified confidence interval

This is n when M = 0.08, \sigma = \sqrt{1.21} = 1.1.

M = z*\frac{\sigma}{\sqrt{n}}

0.08 = 2.327*\frac{1.1}{\sqrt{n}}

0.08\sqrt{n} = 2.327*1.1

\sqrt{n} = \frac{2.327*1.1}{0.08}

(\sqrt{n})^{2} = (\frac{2.327*1.1}{0.08})^{2}

n = 1024

The minimum sample size required to create the specified confidence interval is 1024.

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