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Bingel [31]
3 years ago
10

3 less than the quotient of 20 and x

Mathematics
1 answer:
UkoKoshka [18]3 years ago
3 0
It would be (20/x) -3
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PLEASE HELP...I WILL GIVE BRAINLIEST AND THANKS
a_sh-v [17]

9514 1404 393

Answer:

  see the attachment for a graph

  (x, y) = (0.5, 2.5)

Step-by-step explanation:

The first equation has a slope of 1 and a y-intercept of 2.

The second equation has a slope of -1 and a y-intercept of 3.

The two lines cross at the point (0.5, 2.5), which is the solution to the system of equations.

4 0
3 years ago
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Sam takes a taxi in Chicago. The taxi charges $0.75 per mile and a flat fee of $1.60. If he has at most 10 dollars
Anni [7]
10 - 1.60= 8.40
8.40/0.75=11.2 miles
5 0
3 years ago
Hannah has a small circular table. The radius of the tabletop is 23 cm.
ale4655 [162]
Area of circle = πr2 = π(23)^2
7 0
3 years ago
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HELP!
Readme [11.4K]

Answer: You have a better chance if you do not replace the red marble.

Step-by-step explanation:

The bag has:

5 red marbles

8 blue marbles

4 yellow marbles

3 green marbles

A total of 5 + 8 + 4 + 3 = 20

You want to draw a red marble and then a blue marble.

The probability of drawing a red marble in your first attempt is the number of red marbles divided the total number of marbles:

P1 = 5/20  

now you want to draw a blue marble.

If you replace the red marble, you have 20 marbles again in the bag, then the probability of drawing a blue marble is:

P2 = 8/20

The joint probability is P = P1*P2 = (5/20)*(8/20) = 0.1

If you do not replace the red marble, you have 19 total marbles in the bag, then the probability of taking a blue marble is:

P2 = 8/19

The joint probability is:

P = P1*P2 = (5/20)*(8/19) = 0.105

The probability is slightly bigger if you do not replace the red marble.

7 0
4 years ago
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A consumer organization estimates that over a​ 1-year period 20​% of cars will need to be repaired​ once, 5​% will need repairs​
gtnhenbr [62]

Answer:

a) 0.5476

b) 0.0676

c) 0.4524

Step-by-step explanation:

Given this information, we can conclude that 74% of the cars won't need any repairs over a 1-year period (100 - 20 - 5 - 1 = 74%). And 26% will need at least 1 repair over a 1-year period.

P(car doesn't need repair) = 0.74

P (car needs repair) = 0.26

If you own two cars, the probability that:

<u>a) Neither will need repair:</u>

We need that car 1 won't need repair AND car 2 won't need repair.

=P(Car 1 doesn't need repair) x P(Car 2 doesn't need repair)

= 0.74 x 0.74 = 0.5476

The probability that neither will need repair is 0.5476.

<u>b) Both will need repair:</u>

We need that car 1 needs repair AND car 2 needs repair.

P(Car 1 needs repair) x P(Car 2 needs repair)

= 0.26 x 0.26 = 0.0676

The probability that both will need repair is 0.0676

<u>c) At least one car will need repair</u>

Car 1 needs repair or Car 2 needs repair or both need repair.

To solve this one, it's easier to use the complement of P(neither needs repair)

1 - P(neither needs repair)

1 - (0.74)(0.74)  = 1 - 0.5476 = 0.4524

The probability that at least one car will need repair is 0.4524

4 0
3 years ago
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