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ValentinkaMS [17]
3 years ago
11

Given that f (x) x^2 - 3x find f(-4)

Mathematics
1 answer:
Misha Larkins [42]3 years ago
6 0

Answer:

28

Step-by-step explanation:

If you put -4 into all of the xs, then you should end up with the answer 28.

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What is the estimate of 324+285
Lorico [155]
Exact = 609.

Estimate to 10s = 610.

Estimate to 100s = 600.
4 0
4 years ago
Read 2 more answers
The annual precipitation amounts in a certain mountain range are normally distributed with a mean of 104 inches, and a standard
dsp73

Answer:

91.92% probability that the mean annual precipitation during 49 randomly picked years will be less than 106.8 inches

Step-by-step explanation:

To solve this question, we need to understand the normal probability distribution and the central limit theorem.

Normal probability distribution:

Problems of normally distributed samples are solved using the z-score formula.

In a set with mean \mu and standard deviation \sigma, the zscore of a measure X is given by:

Z = \frac{X - \mu}{\sigma}

The Z-score measures how many standard deviations the measure is from the mean. After finding the Z-score, we look at the z-score table and find the p-value associated with this z-score. This p-value is the probability that the value of the measure is smaller than X, that is, the percentile of X. Subtracting 1 by the pvalue, we get the probability that the value of the measure is greater than X.

Central limit theorem:

The Central Limit Theorem estabilishes that, for a random variable X, with mean \mu and standard deviation \sigma, the sample means with size n of at least 30 can be approximated to a normal distribution with mean \mu and standard deviation s = \frac{\sigma}{\sqrt{n}}

In this problem, we have that:

\mu = 104, \sigma = 14, n = 49, s = \frac{14}{\sqrt{49}} = 2

What is the probability that the mean annual precipitation during 49 randomly picked years will be less than 106.8 inches

This is the pvalue of Z when X = 106.8. So

Z = \frac{X - \mu}{\sigma}

By the Central Limit Theorem

Z = \frac{X - \mu}{s}

Z = \frac{106.8 - 104}{2}

Z = 1.4

Z = 1.4 has a pvalue of 0.9192

0.9192 = 91.92% probability that the mean annual precipitation during 49 randomly picked years will be less than 106.8 inches

8 0
4 years ago
Suppose that the useful life of a car battery, measured in months, decays with parameter 0.03 . We are interested in the life of
scZoUnD [109]

Answer:

a) X ~ e(0.03)

b) μ = 100/3

c) \sigma = 100/3

d) A battery is expected to last 100/3 months (33 months and 10 days approximately).

e) For seven batteries, i would expect them to last 700/3 months (approximately 19 years, 5 months and 10 days).

Step-by-step explanation:

a) The life of a battery is usually modeled with an exponential distribution X ~ e(0.03)

b) The mean of X is μ = 1/0.03 = 100/3

c) The standard deviation is \sigma = 1/0.03 = 100/3

d) The expected value of the bateery life is equal to its mean, hence it is 100/3 months.

e) The expected value of 7 (independent) batteries is the sum of the expected values of each one, hence it is 7*100/3 = 700/3 months.

4 0
3 years ago
Kermit's favorite iced tea is made with 15 tea bags in every 2 liters of water. Peggy made a 12-liter batch of iced tea with 90
AlladinOne [14]
It is just right

Tea. 15. 90.
——- = —— = ———-
Liters 2. 12. When you multiply each by 6 you wil get the other amount it is just grater x6
5 0
3 years ago
Help me with this!!!
gulaghasi [49]

Answer: (3,3)

Midpoint formula = (\frac{x1+x2}{2} , \frac{y1+y2}{2})

6 + 0 / 2 = 2

1 + 5 / 2 = 7

3 0
3 years ago
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