Hey there!!
Fill in the blanks :-
⇒ First graph the line. Locate the <u>value of x </u>on the x-axis. Draw a vertical line from <u>point plotted on the x-axis </u>to the graph of the function and a horizontal line segment from the graph of the function to the y-axis.
<em>Find the value of f(x) when x is -2. </em>
Remember :- <u><em>f(x) is basically the y-value. It is just denoted as _f(x), it stands for function of x. Which means, the value of y, depends upon the value of x or the function of x. </em></u>
Given : x = - 2
Plugging in the values :
... 
... 
... 
The last fill in the blank :
The value of y on the y-axis is the value of the function. Therefore, the value of f(x) is <u>-7 </u>when x is -2.
Hope it helps!!
Answer:
The last one, 14 3/4
Step-by-step explanation:
I hope this helped :)
Let the two numbers be x and y
Then
x + y = 60
And
x - y = 2
x = y + 2
Putting the value of x in the first equation we get
x + y = 60
y + 2 + y= 60
2y + 2 = 60
2y = 60 - 2
2y = 58
y = 58/2
y = 29
Now putting the value of y in the first equation we get
x + y = 60
x + 29 = 60
x = 60 - 29
x = 31
So the value of the two numbers comes out to be 31 and 29. I hope the procedure is clear enough for you to understand.
Answer: 2/4=1/2
Step-by-step explanation: 4-2=2. 7-3=4
Answer:
651.
Step-by-step explanation:
Note: In the given series it should be -29 instead of 29 because 29 cannot be a term of AP whose first term is 91 and common difference is -6.
Consider the given series is
It is the sum of an AP. Here,
First term = 91
Common difference = 85 - 91 = -6
Last term = -29
nth term of an AP is
where, a is first term and d is common difference.
Sum of AP is
![Sum=\dfrac{n}{2}[\text{First term + Last term}]](https://tex.z-dn.net/?f=Sum%3D%5Cdfrac%7Bn%7D%7B2%7D%5B%5Ctext%7BFirst%20term%20%2B%20Last%20term%7D%5D)
![Sum=\dfrac{21}{2}[91+(-29)]](https://tex.z-dn.net/?f=Sum%3D%5Cdfrac%7B21%7D%7B2%7D%5B91%2B%28-29%29%5D)
![Sum=\dfrac{21}{2}[62]](https://tex.z-dn.net/?f=Sum%3D%5Cdfrac%7B21%7D%7B2%7D%5B62%5D)
Therefore, the sum of given series is 651.
