What would 2 x (x-3) sum be

Find the volume of a pyramid with a square base, where the perimeter of the base is 7.3\text{ ft}7.3 ft and the height of the py

Cloud [144]

Answer:

$V=6.66\ ft^3$

Step-by-step explanation:

The perimeter of the square base of a pyramid = 7.3 ft

The height of the pyramid, h = 6ft

The perimeter of a square is given by :

P = 4s, s is the side of square

7.3 = 4s

s = 1.825 ft

The volume of a pyramid is given by :

$V=\dfrac{lbh}{3}$

Here, l = b = 1.825 ft

So,

$V=\dfrac{1.825\times 1.825\times 6}{3}\\\\V=6.66\ ft^3$

So, the volume of the pyramid is equal to $6.66\ ft^3$ .

3 0

3 years ago

If a = 7 and b = 3 find the value of 2a + b

weeeeeb [17]

Answer is 17.

Both values are given where:
a = 7 and b = 3

Substitute the values into the given expression.

( 2 x 7 ) + 3

14 + 3 = 17

Hope it helps :]

5 0

2 years ago

Read 2 more answers

A real estate agent has 14 properties that she shows. She feels that there is a 50% chance of selling any one property during a

Ratling [72]

Answer:

91.02% probability of selling more than 4 properties in one week.

Step-by-step explanation:

For each property, there are only two possible outcomes. Either it is sold, or it is not. The chance of selling any one property is independent of selling another property. So we use the binomial probability distribution to solve this question.

Binomial probability distribution

The binomial probability is the probability of exactly x successes on n repeated trials, and X can only have two outcomes.

$P(X = x) = C_{n,x}.p^{x}.(1-p)^{n-x}$

In which $C_{n,x}$ is the number of different combinations of x objects from a set of n elements, given by the following formula.

$C_{n,x} = \frac{n!}{x!(n-x)!}$

And p is the probability of X happening.

In this problem we have that:

$n = 14, p = 0.5$

Compute the probability of selling more than 4 properties in one week.

Either you sell 4 or less properties in one week, or you sell more. The sum of the probabilities of these events is decimal 1. So

$P(X \leq 4) + P(X > 4) = 1$

We want to find $P(X > 4)$ . So

$P(X > 4) = 1 - P(X \leq 4)$

In which

$P(X \leq 4) = P(X = 0) + P(X = 1) + P(X = 2) + P(X = 3) + P(X = 4)$

So

$P(X = x) = C_{n,x}.p^{x}.(1-p)^{n-x}$

$P(X = 0) = C_{14,0}.(0.5)^{0}.(0.5)^{14} = 0.000061$

$P(X = 1) = C_{14,1}.(0.5)^{1}.(0.5)^{13} = 0.000854$

$P(X = 2) = C_{14,2}.(0.5)^{2}.(0.5)^{12} = 0.0056$

$P(X = 3) = C_{14,3}.(0.5)^{3}.(0.5)^{11} = 0.0222$

$P(X = 4) = C_{14,4}.(0.5)^{4}.(0.5)^{10} = 0.0611$

So

$P(X \leq 4) = P(X = 0) + P(X = 1) + P(X = 2) + P(X = 3) + P(X = 4) = 0.000061 + 0.000854 + 0.0056 + 0.0222 + 0.0611 = 0.0898$

Finally

$P(X > 4) = 1 - P(X \leq 4) = 1 - 0.0898 = 0.9102$

91.02% probability of selling more than 4 properties in one week.

8 0

3 years ago

A parachutist's speed during a free fall reaches 75 meters per second. What is this speed in feet per second? At this speed, how

Alex

Polly uses a probability simulator to pull colored ribbons from a bag 60 times and to flip a coin 60 times. The results are shown in the tables below:

Color of RibbonNumber of Times PulledWhite25Green14Orange21

HeadsTails3822

Using Polly's simulation, what is the probability of pulling an orange ribbon and the coin landing on tails?

3 0

3 years ago

Read 2 more answers

Instructions:Type the correct answer in each box. Use numerals instead of words. If necessary, use / for the fraction bar(s). Si

ollegr [7]

6j+1/3n=134
Hope this helps!!

4 0

3 years ago