All categories

2 years ago

What would 2 x (x-3) sum be

Mathematics

1 answer:

brilliants [131]2 years ago

4 0

Answer:

2x-6 I think

Step-by-step explanation:

You might be interested in

Students are given 3 minutes to complete each multiple-choice question on a test and 8 minutes for each free-response question.

scoundrel [369]

Answer:

8(15 – m)

Step-by-step explanation:

Just Did The Test

7 0

3 years ago

Read 2 more answers

A boulder falls off the top of a cliff during a storm. The cliff is 90 feet high.

andreev551 [17]

Answer:

It will take the boulder approximately 4.28 seconds to hit the road

Step-by-step explanation:

The given height of the cliff from which the boulder falls, h = 90 feet

The equation that can be used to find the time it takes the boulder to fall is h = u·t + (1/2)·g·t²

Where;

h = The height of the cliff = 90 ft.

u = The initial velocity of the boulder = 0 m/s (The boulder is assumed to be at rest when it falls)

g - The acceleration due to gravity ≈ 9.81 m/s²

t = How long it will take for the boulder to hit the road below

Plugging in the values gives;

90 = 0 × t + (1/2)×9.81×t² = 4.905·t²

∴ t = √(90/4.905) ≈ 4.28

The time it takes the boulder to hit the road, t ≈ 4.28 seconds.

7 0

3 years ago

The table displays the amount of time, in minutes, Jordan rode his bike for five days. How many total hours did Jordan ride his

Zinaida [17]

Answer:98.9276

Step-by-step explanation:

The table displays the amount of time, in minutes, Jordan rode his bike for five days. How many total hours did Jordan ride his bike in the five days? DayTime (minutes)11 4545 22 109109 33 5151 44 121121 55 3838 Jordan rode his bike total hours in the five days.

8 0

2 years ago

Find the Maclaurin series for f(x) using the definition of a Maclaurin series. [Assume that f has a power series expansion. Do n

aliya0001 [1]

Answer:

$f(x)=\sum_{n=1}^{\infty}(-1)^{(n-1)}2^{n}\dfrac{x^n}{n}$

Step-by-step explanation:

The Maclaurin series of a function f(x) is the Taylor series of the function of the series around zero which is given by

$f(x)=f(0)+f^{\prime}(0)x+f^{\prime \prime}(0)\dfrac{x^2}{2!}+ ...+f^{(n)}(0)\dfrac{x^n}{n!}+...$

We first compute the n-th derivative of $f(x)=\ln(1+2x)$ , note that

$f^{\prime}(x)= 2 \cdot (1+2x)^{-1}\\f^{\prime \prime}(x)= 2^2\cdot (-1) \cdot (1+2x)^{-2}\\f^{\prime \prime}(x)= 2^3\cdot (-1)^2\cdot 2 \cdot (1+2x)^{-3}\\...\\\\f^{n}(x)= 2^n\cdot (-1)^{(n-1)}\cdot (n-1)! \cdot (1+2x)^{-n}\\$

Now, if we compute the n-th derivative at 0 we get

$f(0)=\ln(1+2\cdot 0)=\ln(1)=0\\\\f^{\prime}(0)=2 \cdot 1 =2\\\\f^{(2)}(0)=2^{2}\cdot(-1)\\\\f^{(3)}(0)=2^{3}\cdot (-1)^2\cdot 2\\\\...\\\\f^{(n)}(0)=2^n\cdot(-1)^{(n-1)}\cdot (n-1)!$

and so the Maclaurin series for f(x)=ln(1+2x) is given by

$f(x)=0+2x-2^2\dfrac{x^2}{2!}+2^3\cdot 2! \dfrac{x^3}{3!}+...+(-1)^{(n-1)}(n-1)!\cdot 2^n\dfrac{x^n}{n!}+...\\\\= 0 + 2x -2^2 \dfrac{x^2}{2!}+2^3\dfrac{x^3}{3!}+...+(-1)^{(n-1)}2^{n}\dfrac{x^n}{n}+...\\\\=\sum_{n=1}^{\infty}(-1)^{(n-1)}2^n\dfrac{x^n}{n}$

3 0

3 years ago

Expand ( 2 − x ) 5 and identify each part of the expression.

dimaraw [331]

You use distributive property. So (5 x 2)-(5 x x)= 10 - 5x.

8 0

4 years ago