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3 years ago

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A tank can hold 300 cm^3 of water. How much would Tim have to pay If he has to fill 12 such tanks with water at 25 cents per cm^

3 ?

1 answer:

katrin [286]3 years ago

8 0

What class is this for?

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Quadrilateral ABCD is a rhombus with an area of 20 square inches.

Ugo [173]

Answer:

area of rhombus =1/2 d1×d2

20=1/2 ×10×d2

d2=4

intersection of diagonal make right angle and cut in equal parts

d1/2=10/2=5

d2/2=4/2=2

use Pythagoras in right angle to bide side

side^2= 5^2 +2^2

side = √29

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3 years ago

You have an equation y=x+7. Is the ordered pair (1,6) a solution? Yes or no?

vaieri [72.5K]

Answer:
no

step-by-step explanation:
y=x+7
x is the slope of 1
7 is the y-intercept
because 7 is the y-intercept and the slope is positive it never touches (1,6)

8 0

3 years ago

What is the equation of the line that passes through the point (-3, 0) and has a slope of -1/3?

ANTONII [103]

Answer:

Y=-1/3x-1

Step-by-step explanation:

Y-0=-1/3(x+3)

5 0

3 years ago

Calculate the capacity in liters of a tin 20m by 15m by 10m.

rusak2 [61]

20 * 15 * 10 *10^-6
= 0.003

5 0

3 years ago

Write the ratio for sin A and cos A. The triangle is not drawn to scale.

Zolol [24]

Option A:

$$ \sin A= \frac{14}{50}, \ \cos A= \frac{48}{50}$

Solution:

Given data:

AB = 50, BC = 48, AC = 14

To find the value of sin A and cos A:

$$\sin A= \frac{Opposite \ side}{Hypotenuse}$

$$\sin A= \frac{AC}{AB}$

$$\sin A= \frac{14}{50}$

$$\cos A= \frac{Adjacent \ side}{Hypotenuse}$

$$\cos A= \frac{BC}{AB}$

$$\cos A= \frac{48}{50}$

$$\therefore \ \sin A= \frac{14}{50}, \ \cos A= \frac{48}{50}$

Hence option A is the correct answer.

7 0

3 years ago