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Korvikt [17]
3 years ago
13

Which value, when placed in the box, would result in a system of equations with infinitely many solutions?

Mathematics
2 answers:
tamaranim1 [39]3 years ago
7 0

Answer:

-10

Step-by-step explanation:

PSYCHO15rus [73]3 years ago
4 0
For a system of equations to have infinitely many solutions it must describe identical lines.
If you multiply the first equation by 2, then move the x term to the left side, you would get 2y-4x=-10
Final Answer:
-10
Hope I helped :)
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What is the solution to the equation?
Gelneren [198K]

Answer:

Hello,

answer B

2

Step-by-step explanation:

\dfrac{2}{x} -\dfrac{x}{x+5} =\dfrac{10}{x^2+5x} \\\\we\ suppose\ x\neq 0\ and\ x\neq -5\\\\\text{Reducing to the same denominator}\\\dfrac{2(x+5)-x^2}{x(x+5)} =\dfrac{10}{x^2+5x} \\\\Simplify\ by\ x^2+5x\\\\2x+10-x^2=10\\\\-x^2+2x=0\\\\-x(x-2)=0\\\\roots\ are\ 2 \ and\ 0\ (to\ be\ excluded)\\\\Root=2\\

3 0
3 years ago
What is the commutative and associative propertys?
timama [110]

Answer:

<u>Commutative property:</u> states that the order in which we multiply numbers does not change the product.

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5 0
3 years ago
Plzzzzzz ans this quickly plzz
elixir [45]

Step-by-step explanation:

8.

Prime factorization of 48 is :

48=2\times  2 \times  2 \times  2 \times  3\\\\=2^4\times  3^1

Option (3) is true.

9.

Prime factorization of 19 is:

19 = 19 × 1

Option (c) is correct.

(10).

Prime factorization of 924 is:

924 = 2 x 2 x 3 x 7 x 11

= 2² x 3¹ x 7¹ x 11¹

Hence, this is the required solution.

5 0
3 years ago
PLZ HELP!!!!!!!!!!!!
Nezavi [6.7K]

Answer:

1. 0.5

2. 0.25

3.  0.33333...

4.  0.2

5.  0.75

6. 0.666...

7. 0.4

8. 0.375

9. 0.444...

10. 0.28571428571429

Step-by-step explanation:

6 0
3 years ago
A point H is 20m away from the foot of a tower on the same horizontal ground. From the point H, the angle of elevation of the po
astra-53 [7]

Answer:

a. See Attachment 1

b. PT = 12.3\ m

c. HT = 31.1\ m

d. OH = 28.4\ m

Step-by-step explanation:

Calculating PT

To calculate PT, we need to get distance OT and OP

Calculating OT;

We have to consider angle 50, distance OH and distance OT

The relationship between these parameters is;

tan50 = \frac{OT}{20}

Multiply both sides by 20

20 * tan50 = \frac{OT}{20} * 20

20 * tan50 = OT

20 * 1.1918 = OT

23.836  = OT

OT = 23.836

Calculating OP;

We have to consider angle 30, distance OH and distance OP

The relationship between these parameters is;

tan30 = \frac{OP}{20}

Multiply both sides by 20

20 * tan30 = \frac{OP}{20} * 20

20 * tan30 = OP

20 * 0.5774= OP

11.548 = OP

OP = 11.548

PT = OT - OP

PT = 23.836 - 11.548

PT = 12.288

PT = 12.3\ m (Approximated)

--------------------------------------------------------

Calculating the distance between H and the top of the tower

This is represented by HT

HT can be calculated using Pythagoras theorem

HT^2 = OT^2 + OH^2

Substitute 20 for OH and OT = 23.836

HT^2 = 20^2 + 23.836^2

HT^2 = 400 + 568.154896

HT^2 = 968.154896

Take Square Root of both sides

HT = \sqrt{968.154896}

HT = 31.1\ m <em>(Approximated)</em>

--------------------------------------------------------

Calculating the position of H

This is represented by OH

See Attachment 2

We have to consider angle 50, distance OH and distance OT

The relationship between these parameters is;

tan50 = \frac{OH}{OT}

Multiply both sides by OT

OT * tan50 = \frac{OH}{OT} * OT

OT * tan50 = {OH

OT * 1.1918 = OH

Substitute OT = 23.836

23.836 * 1.1918 = OH

28.4= OH

OH = 28.4\ m<em> (Approximated)</em>

5 0
3 years ago
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