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garik1379 [7]
2 years ago
13

PLZ HELP!!!!!!!!!!!!

Mathematics
1 answer:
Nezavi [6.7K]2 years ago
6 0

Answer:

1. 0.5

2. 0.25

3.  0.33333...

4.  0.2

5.  0.75

6. 0.666...

7. 0.4

8. 0.375

9. 0.444...

10. 0.28571428571429

Step-by-step explanation:

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2 years ago
Please answer. In parallelogram WXYZ, diagonals WY and XZ intersect at point A. Give WA=x^2-48 and AY=x^2-6x. What is WY? Show y
netineya [11]

The diagonals of a parallelogram are congruent

The length WY is 32

<h3>How to determine the length WY</h3>

Given that:

WA = x^2 - 48 and

AY = x^2 - 6x

Then, we have:

x^2 - 48 = x^2 - 6xdiagonal

Subtract x^2 from both sides

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The length WY is calculated as:

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So, we have:

WY=2 * [x^2 - 48]

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WY=2 * [8^2 - 48]

Simplify

WY=32

Hence, the length WY is 32

Read more about parallelograms at:

brainly.com/question/10062747

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