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3 years ago

what do you think the sum of the probabilities for all the possible outcomes must be for any situation. explain

1 answer:

4 0

Let's pose this question a different way: what are the chances that one out of all possible events is going to happen? What are the chances that, if I roll a die, I will roll a 1, 2, 3, 4, 5, or a 6? What is the probability, if I flip a coin, that the outcome will either be heads or tails? When we take every possible outcome and add their probabilities together, the sum of the probabilities will be 100%, or 1.

Example:
Coin Toss:
Prob of Heads (.5) plus Prob of Tails (.5) = 1
Dice roll:
1/6 (odds of rolling any given number) times 6 (number of possibilities) = 1

You might be interested in

Find the rational roots f(x) =3x3+ 2x2 + 3x + 6

Ann [662]

The rational roots of f(x) = 3x^3 + 2x^2 + 3x + 6 are ±(1, 2, 3, 6, 1/3, 2/3)

<h3>How to determine the rational root of the function f(x)?</h3>

The function is given as:

f(x) = 3x^3 + 2x^2 + 3x + 6

For a function P(x) such that

P(x) = ax^n +...... + b

The rational roots of the function p(x) are

Rational roots = ± Possible factors of b/Possible factors of a

In the function f(x), we have:

a = 3

b = 6

The factors of 3 and 6 are

a = 1 and 3

b = 1, 2, 3 and 6

So, we have:

Rational roots = ±(1, 2, 3, 6)/(1, 3)

Split the expression

Rational roots = ±(1, 2, 3, 6)/1 and ±(1, 2, 3, 6)/3

Evaluate the quotient

Rational roots = ±(1, 2, 3, 6, 1/3, 2/3, 1, 2)

Remove the repetition

Rational roots = ±(1, 2, 3, 6, 1/3, 2/3)

Hence, the rational roots of f(x) = 3x^3 + 2x^2 + 3x + 6 are ±(1, 2, 3, 6, 1/3, 2/3)

The complete parameters are:

The function is given as:

f(x) = 3x^3 + 2x^2 + 3x + 6

The rational roots of f(x) = 3x^3 + 2x^2 + 3x + 6 are ±(1, 2, 3, 6, 1/3, 2/3)

Read more about rational roots at

brainly.com/question/17754398

#SPJ1

4 0

1 year ago

Point G is the centroid of the right △ABC with m∠C=90° and m∠B=30°. Find AG if CG=4 ft.

o-na [289]

Answer: $\text{Length of AG=}\frac{2\sqrt{63}}{3}$

Explanation:

Please follow the diagram in attachment.

As we know median from vertex C to hypotenuse is CM

$\therefore CM=\frac{1}{2}AB$

We are given length of CG=4

Median divide by centroid 2:1

CG:GM=2:1

Where, CG=4

$\therefore GM=2$ ft

Length of CM=4+2= 6 ft

$\therefore CM=\frac{1}{2}AB\Rightarrow AB=12$

In $\triangle ABC, \angle C=90^0$

Using trigonometry ratio identities

$AC=AB\sin 30^0\Rightarrow AC=6$ ft

$BC=AB\cos 30^0\Rightarrow BC=6\sqrt{3}$ ft

$CN=\frac{1}{2}BC\Rightarrow CN=3\sqrt{3}$ ft

In $\triangle CAN, \angle C=90^0$

Using pythagoreous theorem

$AN=\sqrt{6^2+(3\sqrt{3})^2\Rightarrow \sqrt{63}$

Length of AG=2/3 AN

$\text{Length of AG=}\frac{2\sqrt{63}}{3}$ ft

5 0

3 years ago

Solve 12x-5>-2 please

Stells [14]

Answer:

$x > \frac{1}{4}$

Step-by-step explanation:

$12x - 5 > - 2$

Lets add +5 in both the sides.

$= > 12x - 5 + 5 > - 2 + 5$

$= > 12x > 3$

Now lets divide 12 on both the sides.

$= > \frac{12x}{12} > \frac{3}{12}$

$= > x > \frac{1}{4}$

8 0

3 years ago

A polynomial has zeros x=0, x= -3, X = 4. What are some possible factored equations for this fourth degree polynomial.

kati45 [8]

Answer:

$x^{2} (x + 3)(x - 4)$

Step-by-step explanation:

You can multiply this out to get the full equations.

It's to the 4th degree so the x on the outside has to be squared to add the fourth degree.

To get other zeros:

x + 3 = 0

x = -3

x - 4 = 0

x = 4

Hope this helped. :0)

5 0

3 years ago

Write a percent that has a value between the two decimals 0.4 and 0.5

Juliette [100K]

A percent would be 0.45

5 0

3 years ago