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PilotLPTM [1.2K]
3 years ago
7

I WILL CHOOSE YOU AS Brainliest PLEASEE ANSWER!!

Mathematics
1 answer:
Alona [7]3 years ago
3 0

Answer:

lol, I can not answer your question without the list that the question given. please add

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A rectangular garden is fenced on all sides with 256 feet of fencing. The garden is 8feet longer than it is wide. Find the lengt
Marina86 [1]
Perimeter = 2L + 2W = 256

"8 feet longer than it is wide"
translates to
L = 8 + W

we plug that into the first equation and get
2(8 + W) + 2W = 256
now we solve for W

distribute the 2
16 + 2W + 2W = 256

add like terms
16 + 4W = 256

subtract 16 from both sides
4W = 240

divide both sides by 4
W = 60

plug that into
L = 8 + W
and solve for L now

L = 8 + 60
so
L = 68

therefore your
length = 68
and
width = 60
6 0
3 years ago
How can you tell if a discontinuity of a limit is removable or not removable?
azamat

A discontinuity is present if any of ...

  • the limit doesn't exist
  • the limit is not the same as the value of the function

If the one of these that is the cause of discontinuity is the last one and defining the function will make this issue go away, then the discontinuity is removable.

8 0
3 years ago
Next 4 multiples of 1/6
solniwko [45]

Answer:

2/6 3/64/65/6

Step-by-step explanation:

5 0
3 years ago
4.07, 4.070, 4.70, 4.0700 what value is not equivalent.
larisa [96]
4.70, all the others can be simplified to 4.07 by taking away the zeroes after the 7 because they are not significant, The one before the 7 stays because it is significant as it is holding the tenths place value.
5 0
3 years ago
Read 2 more answers
Solve the equation 3^(2x) -4*3^(x+1) + 27 = 0. use rules of exponents to change 3^(x+1)​
Leviafan [203]

Answer:

\huge\boxed{x=1\ \vee\ x=2}

Step-by-step explanation:

3^{2x}-4\cdot3^{x+1}+27=0\\\\\text{use}\ (a^n)^m=a^{nm}\ \text{and}\ a^n\cdot a^m=a^{n+m}\\\\\left(3^x\right)^2-4\cdot3^x\cdot3^1+27=0\\\\\left(3^x\right)^2-12\cdot3^x+27=0\\\\\text{substitute}\ 3^x=t>0\\\\t^2-12t+27=0\\\\t^2-3t-9t+27=0\\\\t(t-3)-9(t-3)=0\\\\(t-3)(t-9)+0\iff t-3=0\ \vee\ t-9=0\\\\t-3=0\qquad\text{add 3 to both sides}\\\boxed{t=3}\\\\t-9=0\qquad\text{add 9 to both sides}\\\boxed{t=9}

\text{We return to substitution:}\\\\3^x=t\\\\3^x=3\ \vee\ 3^x=9\\\\3^x=3^1\ \vee\ 3^x=3^2\\\\\boxed{x=1}\ \vee\ \boxed{x=2}

4 0
3 years ago
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