How to solve your problem
(4−3)(−22−7−5)
(4x−3)(−2x2−7x−5)(4x-3)(-2x^{2}-7x-5)(4x−3)(−2x2−7x−5)
Simplify
1
Distribute
(4−3)(−22−7−5)
(4x−3)(−2x2−7x−5){\color{#c92786}{(4x-3)(-2x^{2}-7x-5)}}(4x−3)(−2x2−7x−5)
4(−22−7−5)−3(−22−7−5)
2
distribute
4(−22−7−5)−3(−22−7−5)
4x(−2x2−7x−5)−3(−2x2−7x−5){\color{#c92786}{4x(-2x^{2}-7x-5)}}-3(-2x^{2}-7x-5)4x(−2x2−7x−5)−3(−2x2−7x−5)
−83−282−20−3(−22−7−5)
3
−83−282−20−3(−22−7−5)
−8x3−28x2−20x−3(−2x2−7x−5)-8x^{3}-28x^{2}-20x{\color{#c92786}{-3(-2x^{2}-7x-5)}}−8x3−28x2−20x−3(−2x2−7x−5)
−83−282−20+62+21+15
4
Solution
−83−222++15
I know this looks like a lot but its just how you solve your problem.
therefor, your answer is
Solution
−83−222++15
<em>Hope this helps!</em>
<em>Have a great day!</em>
<em>-Hailey</em>
Y=-4+3x is different because all others have a negative 4 AND a -3x
Answer:0.8
Step-by-step explanation:To write 24/30 as a decimal you have to divide numerator by the denominator of the fraction. We divide now 24 by 30 what we write down as 24/30
The consecutive integers are i, i+1, i+2, i+3.
3 less than sum of the integers
= i + i +1 + i + 2 + i + 3 - 3 = 4i + 3
