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3 years ago

9

Find what percentage of 70 is 30.

2 answers:

Debora [2.8K]3 years ago

7 0

30 divided by 70 is about .428. Multiply that by 100 and you have about 42.8%

katrin2010 [14]3 years ago

6 0

30 is 42% of 70 and you divide 30 by 70

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A collection of dimes and nickels is worth $8.40 there are 106 coins how many of each are there

kotegsom [21]

There are 62 dimes and 44 nickels.

N + D = 106 (There are 106 coins in all.)
1 nickel = 5 cents.
1 dime = 10 cents.
5*N + 10*D = 840 ($8.40 = 840 cents)
N + D = 106 -------(1)
N = (106 - D)
5*N + 10*D = 840 ---------(2)
5*(106-D) + 10*D = 840
530 - 5*D + 10*D = 840
5*D = 840 - 530
5*D = 310
D = 310/5 = 62
Eq(1) N + D = 106
N + 62 = 106
N = 106 - 62
N = 44

7 0

3 years ago

Find the permeter of a quadrilateral with vertices at C (2,4), D(1,1), E(5,0), and F(3,4). Round your answer to the nearest hund

denpristay [2]

Answer:

12.76

Step-by-step explanation:

This is much easier to solve if you draw it out on a graph. The perimeter is the sum of all the sides. I used the Pythagorean theorem to find the hypotenuse.

${a}^{2} + {b}^{2} = {c}^{2} \\ c = \sqrt{ {a}^{2} + {b}^{2} }$

$dc = \sqrt{ {3}^{2} + {1}^{2} } = \sqrt{10} \\ cf = 1 \\ fe = \sqrt{ {4}^{2} + {2}^{2} } = \sqrt{20} \\ de = \sqrt{ {1}^{2} + {4}^{2} } = \sqrt{17} \\ \sqrt{10} + 1 + \sqrt{20} + \sqrt{17} = 12.76$

7 0

3 years ago

I need help please!!:)

asambeis [7]

Answer:

No bcuz its not on the line

Step-by-step explanation:

5 0

2 years ago

Read 2 more answers

Please help, this is for 8th grade math.

expeople1 [14]

Answer:

(2,-2)

Step-by-step explanation:

The first step is to substitute y in the first equation with the right side of the second equation because they both equal to y.

-3x+4 = 4x-10

-3x-4x+4-4 = 4x-4x-10-4

-7x = -14

-7x/-7 = -14/-7

x = 2

Plugin 2 for x for either equation to solve for y, I'll be using the second equation, but either one is fine.

y = 4(2)-10

y = 8-10

y = -2

Plugin x = 2 and y = -2 into (x,y), and you get (2,-2)

6 0

3 years ago

Solve the following equation by factoring:9x^2-3x-2=0

olya-2409 [2.1K]

Answer:

The two roots of the quadratic equation are

$x_1= - \frac{1}{3} \text{ and } x_2= \frac{2}{3}$

Step-by-step explanation:

Original quadratic equation is $9x^{2}-3x-2=0$

Divide both sides by 9:

$x^{2} - \frac{x}{3} - \frac{2}{9}=0$

Add $\frac{2}{9}$ to both sides to get rid of the constant on the LHS

$x^{2} - \frac{x}{3} - \frac{2}{9}+\frac{2}{9}=\frac{2}{9}$ ==> $x^{2} - \frac{x}{3}=\frac{2}{9}$

Add $\frac{1}{36}$ to both sides

$x^{2} - \frac{x}{3}+\frac{1}{36}=\frac{2}{9} +\frac{1}{36}$

This simplifies to

$x^{2} - \frac{x}{3}+\frac{1}{36}=\frac{1}{4}$

Noting that (a + b)² = a² + 2ab + b²

If we set a = x and b = $\frac{1}{6}\right)$ we can see that

$\left(x - \frac{1}{6}\right)^2$ = $x^2 - 2.x. (-\frac{1}{6}) + \frac{1}{36} = x^{2} - \frac{x}{3}+\frac{1}{36}$

So

$\left(x - \frac{1}{6}\right)^2=\frac{1}{4}$

Taking square roots on both sides

$\left(x - \frac{1}{6}\right)^2= \pm\frac{1}{4}$

So the two roots or solutions of the equation are

$x - \frac{1}{6}=-\sqrt{\frac{1}{4}}$ and $x - \frac{1}{6}=\sqrt{\frac{1}{4}}$

$\sqrt{\frac{1}{4}} = \frac{1}{2}$

So the two roots are

$x_1=\frac{1}{6} - \frac{1}{2} = -\frac{1}{3}$

and

$x_2=\frac{1}{6} + \frac{1}{2} = \frac{2}{3}$

7 0

1 year ago