B) Minimum= 1
Q1= 3
Q3= 8
Lower Fence= Q1-(IQR*1.5)
= 3-(5*1.5)
= -4.5
Maximum= 11
Median= 7
IQR= 8= 3= 5
Upper Fence= Q3+(IQR*1.5)
= 8+(5*1.5)
= 15.5
c) No. All values are between the lower fence and the upper fence.
Answer:
(1,2)
(3,3)
(-1/2, 11/2)
Step-by-step explanation:
A system of equations is 2 or more equations for which the same x,y solution exists. We can solve the system in three ways: elimination, substitution, or graphing. Substitution can be used by substituting the value of one variable into the equation.
<u>Pair x=3y-5 and x+y=3</u>
Because x=3y-5, we can substitute 3y-5 into x in x+y=3
x+y=3
(3y-5)+y=3
3y-5+y=3
4y-5=3
4y-5+5=3+5
4y=8
y=2
We now substitute y=2 into x=3y-5.
x=3y-5
x=3(2)-5
x=6-5
x=1
<u>Pair y=x and 3x+3y=18</u>
Because y=x, we can substitute x into y in 3x+3y=18
3x+3y=18
3x+3x=18
6x=18
x=3
We now substitute x=3 into y=x.
y=3.
<u>Pair y=-3x+4 and 5x-y=0</u>
Because y=-3x+4, we can substitute -3x+4 into y in 5x-y=0
5x-y=0
5x-(-3x+4)=0
5x+3x+4=0
8x+4=0
8x=-4
x=-1/2
We now substitute x=-1/2 into y=-3x+4
y=-3x+4
y=-3(-1/2)+4
y=3/2+4
y=11/2
The only answer I could think of is Ice-sosceles traingles?
X^3 = 27
x = 3√27
x = 3
The answer is: x = 3.